Plectis

Long paper

The Binary Totient Series

Erdős #249 By July 2026; revised 1 October 2026 Authorship, AI use and citation

Summary. The dyadic totient sections through level e≥1 have an explicit rational basis of size 2e+1. Truncating a scaled tail difference produces an integer whose residue certifies nonintegrality when its distances from both endpoints of the residue interval exceed an explicit error bound. The record develops the resulting finite denominator exclusions, equivalent residue criteria, and sufficient exponential-sum estimates. Rational comparison sequences identify the limitations of particular size, parity, rank, and finite-prefix arguments. The short paper supplies the all-base basis theorem; here each conditional result carries the arithmetic hypothesis still needed to apply it. Those hypotheses are not established in the form required to prove irrationality of S=∑ φ(n)2−n.

This paper covers a claim-bounded problem-specific reasoning surface for Erdős #249: selected checked premises, finite certificates, closed routes, surviving obligations, and their exact evidence bands.

It does not establish the validity of claims tagged Lean, which belongs to the cited kernel-checked source, or a solution to Erdős #249, which remains open.

In this paper

Log-concavity of the Möbius-weighted series

Put Θr=∑n≥0μ(n+1)/(2n+1−1)r, so that Θ2=S−1/2. We prove strict log-concavity for every integer r≥1. This orders the values of the family without determining their rationality.

Definition 6.120. For each integer r≥1, put

Θr=∑n≥0μ(n+1)(2n+1−1)r=1−3−r+∑n≥0μ(n+3)(2n+3−1)r.

The first two summands isolate the dominant contribution. The remaining absolute sum is at most 1/(2r(2r−1)), by comparison with ∑n≥22−rn. In particular, Θr>0 for r≥1: 1−3−r≥2/3 and this tail bound is at most 1/2. Erdos249257.SignedQMomentObstruction.mobiusMersenneTheta Erdos249257.SignedQMomentObstruction.mobiusMersenneTwoAtom Erdos249257.SignedQMomentObstruction.mobiusMersenneTailAfterTwo

Theorem 6.121 (The values at exponents one and two). The first two values are Θ1=1/2 and Θ2=S−1/2.

The second equality is the Möbius-square identity credited in §5.4; whether Θ2 is rational is #249 itself.

Theorem 6.122 (The first two summands give a positive Hankel gap). (1−3−(r+1))2−(1−3−r)(1−3−(r+2))=4/3r+2, so the rational sequence 1−3−r is strictly log-concave for every integer r≥1.

Theorem 6.123 (Strict log-concavity for all integer r≥1). For every integer r≥1,

ΘrΘr+2<Θr+12.

Equivalently, the determinant of (ΘrΘr+1Θr+1Θr+2) is negative. The two-summand comparison gives an elementary proof, detailed below; the same strict inequality is also proved in Lean.

A quantitative comparison. For this proof put ar=1−3−r and εr=1/(2r(2r−1)). The preceding bound gives |Θr−ar|≤εr. Since 0<ar<1, expansion of the two products gives

Θr+12−ΘrΘr+2≥43r+2−Br,Br=2εr+1+εr+12+εr+εr+2+εrεr+2.

Here εr+1<εr/4, so Br+1<Br/4. The rational comparison

B5=5010659332001951744<437

therefore proves the inequality for all r≥5: the error decreases faster than the positive main term. For r=1,2,3,4, truncate each Θj at n=8. Its omitted absolute sum is at most

1(29−1)j(1−2−j).

Using Θ1=1/2 and these rational intervals, the four gaps Θr+12−ΘrΘr+2 are respectively greater than 1/4, 1/16, 1/64 and 1/200. These finite rational comparisons complete the ordinary proof. ◻

Observation 6.124. The inequality excludes a representation Θr=∫0∞xrdν(x) by a positive measure with these finite moments: Cauchy–Schwarz would give Θr+12≤ΘrΘr+2. It does not by itself imply irrationality of Θ2. Indeed, the rational sequence 1−3−r satisfies the same strict log-concavity inequalities. Thus the determinant sign supplies an obstruction to a positive-moment representation, not a rational-approximation estimate.

The accompanying formal results include a rectangular determinant expansion derived from the Leibniz formula (Erdos249257.SignedQMomentObstruction.det_mul_rectangular), and the following elementary parity fact: in a finite sum of dyadic fractions, if the largest denominator exponent occurs once and its numerator is odd, clearing that denominator gives an odd numerator (Erdos249257.SignedQMomentObstruction.scaled_dyadic_sum_odd).

About this paper

Authorship and AI use. Will Cook built and directed the research infrastructure and maintains the public release. He reviewed claims when he could. AI agents did most of the research and drafting. Cook did not independently verify every claim.

Cite and contact. Cite this paper by its title, author and date above, with its PDF; cite the earlier sources it uses for a mathematical result. For software, use the release citation and give the commit used. Contact Will with questions or corrections.

Prefer the manuscript?

Equations typeset from the exact TeX. Rendered from the LaTeX manuscript source with file fingerprint sha256:2be13b340f9dafc4. Its file fingerprint matched the published source record, so the PDF above, the LaTeX, and this page are one manuscript. Redeploying the site regenerates this page from whatever the public repository holds at that moment.