Plectis

Long paper

The Binary Totient Series

Erdős #249 By July 2026; revised 1 October 2026 Authorship, AI use and citation

Summary. The dyadic totient sections through level e≥1 have an explicit rational basis of size 2e+1. Truncating a scaled tail difference produces an integer whose residue certifies nonintegrality when its distances from both endpoints of the residue interval exceed an explicit error bound. The record develops the resulting finite denominator exclusions, equivalent residue criteria, and sufficient exponential-sum estimates. Rational comparison sequences identify the limitations of particular size, parity, rank, and finite-prefix arguments. The short paper supplies the all-base basis theorem; here each conditional result carries the arithmetic hypothesis still needed to apply it. Those hypotheses are not established in the form required to prove irrationality of S=∑ φ(n)2−n.

This paper covers a claim-bounded problem-specific reasoning surface for Erdős #249: selected checked premises, finite certificates, closed routes, surviving obligations, and their exact evidence bands.

It does not establish the validity of claims tagged Lean, which belongs to the cited kernel-checked source, or a solution to Erdős #249, which remains open.

In this paper

LCM tails and rational comparisons

We first specialise the tail congruence to LCM shifts, then compare it with rational series preserving selected coefficient data. The source declarations accompany the formulas; references point to the complete constructions and their hypotheses in the preceding sections.

  1. Tail differences at least common multiples. Let Ha=lcm⁡(1,…,2a). Then S is irrational if and only if, beyond every threshold a0, some a≥a0 satisfies ΔHa(Ha)∉Z. This is the exact cofinal nonintegrality criterion for the actual LCM diagonal, not a quantitative separation estimate and not a proof that such indices occur; the forward implication is recorded separately.

  2. Positive tail differences need not be nonintegral. For a≥8 and J+(a+6)<2⋅2a, one has ΔHa(Ha+J)>0. Suppose this difference is an integer. If a truncation depth K satisfies

    J+K+(a+6)<2⋅2a,2Ha+J+K+2<2K,

    then

    DHa,Ha+J,Kmod2K=2K−ΔHa(Ha+J+K)

    lies strictly between 2K−(2Ha+J+K+2) and 2K. The later tail difference is a positive integer; its negative is the representative near zero. Thus positivity determines which endpoint contains the residue, but does not exclude an integral tail difference. Both displayed bounds on K are required for this conclusion. Source declarations: positive tail differences, negative endpoint representative, residue near the upper endpoint.

  3. Divisibility and finite linear combinations do not suffice. A dyadic coboundary is a sequence of the form 2uj−uj+1; its weighted sum telescopes. For every t≥3, with H=lcm⁡(1,…,t), the linked source constructs a nonzero comparison sequence of this form. Its coefficients reproduce the actual totient differences at t−2 prescribed indices and are divisible by φ(H). Every finite integer linear combination of forward shifts preserves the telescoping identity and divisibility by φ(H) and the corresponding lower-level factors. The bounds remain uniform in the index, but are multiplied by the sum of the absolute values of the combination’s coefficients. A variant preserves sparse prescribed values along entire arithmetic progressions. These properties alone do not force a contradiction: the comparison need not consist of actual totient differences. The theorem concerns linear combinations of shifts, not nonlinear operations, and does not supply certificates at arbitrarily large scales. Source declarations: obstruction for finite integer combinations of shifts.

If S=a/v with integers a and v≥1, the scaled tails uN=vRN are integers and satisfy

uN+1=2uN−vφ(N+1),0≤uN≤v(N+2).

In particular uN/2N→0. Its dyadic sections n↦u2jn+r have rational rank at least 2e−1 through level e and a common eventual period modulo v. Both properties are the corresponding theorem for the same carry; they are compatible, and neither supplies a contradiction.

Section 12.6 constructs a rational comparison sequence with c(n)=φ(n) for odd n, |c(n)−φ(n)|≤2 for even n, 0≤c(n)≤n, and

∑n≥1c(n)2−n=54.

This comparison sequence has an integral carry satisfying uN/2N→0, with dyadic rank at least 2e−1 at every level. Thus the same lower bound for a hypothetical totient carry is compatible with rationality. For one fixed prime p and g:N→Z, the exact laws g(pn)=pg(n) when p∣n and g(pn)=(p−1)g(n) otherwise, together with g−φ=o(n), force g=φ: a nonzero defect keeps a nonzero ratio to the argument along pjn. The comparison sequence fails these dilation laws. The unchanged odd-residue sections also give coefficient rank at least 2e−1 at every level. This is a lower bound, not an exact formula for the full coefficient rank.

About this paper

Authorship and AI use. Will Cook built and directed the research infrastructure and maintains the public release. He reviewed claims when he could. AI agents did most of the research and drafting. Cook did not independently verify every claim.

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