Introduction
Let
is
irrational [1][2] [3]. Summation by parts
gives
The support and every modulus cutoff are fixed before the target is
chosen. The interval contains rational and irrational sums with the same
eventual coefficient and partial-sum residues. A block changes only when
it meets the support, whereas every correction enters the dyadic sum.
With polylogarithmic corrections, empirical block laws agree
asymptotically at lengths
We use a standard interval-covering argument for series with finite choices. Fridy’s generalised-base lemma [5] treats prescribed digit bounds and nonincreasing weights. Crmarić and Kovač [17] give the finite-choice form used here, and Kovač and Tao [6] use analogous intervals of reciprocal choices. We must arrange these choices on a sparse set while preserving cumulative congruences. To do so, we redistribute a fixed correction between two adjacent indices. The simplest useful calculation is
Moving
Throughout,
For integers
Proposition 1.1 (sparse changes preserving
congruences). Let
For each integer
In particular the distance tends
to zero for every integer-valued
The cutoff may depend on
Section 2 proves the construction and Section 3 transfers the stated prime-gap properties. For the actual primes, integral tail shifts characterise rationality. Two consecutive small differences with unequal gaps give a sufficient condition for irrationality. Finite enclosures certify individual witnesses without supplying arbitrarily late ones. The companion’s literature discussion contains the further comparisons, including finite subsums and other dyadic coefficient sequences.
Proof of Proposition 1.1
Proof. Fixed totals. Use
Let
For integers
and put
The ordinary total contains no
After
The entry
Spacing and size. The choices at stage
Because
No monotonicity of the weights is needed. Each
entry of (1) is at most
To allow a nonmonotone bound
This nondecreasing lower envelope tends to
infinity even when
The maximum
exists:
Let
Attaining the interval. The support and congruence requirements are now settled independently of the target. Only the digits remain to be chosen. Define
Even zero digits contribute
Taking
These bounds do not yet prove that every point
of
These intervals meet or overlap by (3), and their union is
This figure is drawn in the PDF.
Given
The covering just proved makes this possible at every stage. Since
Thus every
The logarithmic scale. For
with
at each coordinate
Choose the same uniform starting index
For
No limiting block law is assumed. A block-only test bounded in
absolute value by
Application to prime gaps
The elementary bound
Corollary 3.1 (a rational sum with the stated
prime-gap statistics). Let
Moreover, with
These positions are not asserted to be prime.
Proof. Apply Proposition 1.1 to
The first count is
To estimate
◻
For
Land’s draft [8] proves conditional irrationality under a uniform Hardy–Littlewood hypothesis of the kind formulated by Kuperberg [7]. Ringer’s draft [16] obtains conditional normality. Their quantitative prime-pattern hypotheses are stronger than the absolute block comparison above and are not assumed here. The companion’s Section 3 compares the hypotheses and sampling conventions.
The prime series and its actual tails
We now study complete tails of the actual prime gaps. Put
Theorem 4.1 (prime-to-gap identity). The actual
prime and gap series satisfy
satisfy
Proof. Finite summation by parts gives
Since
Tao noted this reduction in the problem’s forum discussion [15].
Corollary 4.2 (exact irrationality reformulation). The prime-value dyadic series is irrational if and only if the prime-gap dyadic series is. Both series converge by the polynomial bound proved above; neither side is proved irrational.
Proof. Adding the rational number
The index
Lemma 4.3 (the boundary condition for the tail
recurrence). Let
Proof. Iteration gives
Integral shifts
For
Theorem 4.4 (exact rationality classification).
For a real integer-coefficient recurrence, the following are equivalent:
Consequently
Proof. Iteration gives
An integral shift with
The classification applies to any integer-coefficient recurrence;
Lemma 4.3 is needed
only to identify complete tails. The periodicity is of fractional parts,
not necessarily tail values. For the positive even coefficients
Small tail differences and finite tests
Fix
Proposition 5.1 (two consecutive differences of
absolute value less than one). Let
In
that case
Proof. The bounds on
The endpoints cannot be included: when
Problem 5.2 (two small tail differences at arbitrarily
large indices). For every integer
Theorem 4.4 requires nonintegrality, not smallness; (4) is only a sufficient condition. All three requirements must hold at the same arbitrarily late indices. Separate infinite sets need not intersect.
By Proposition 5.1, such an index
must have
Finite separation from the integers
An enclosure certifies nonintegrality only when it misses every
integer. Choose
Splitting
the complete tails after
The uncomputed term is a
rescaled later complete tail difference with the same shift
For the actual prime gaps, one computable choice is
Proposition 5.3 (finite separation criterion). If
for every
then
Proof. The enclosure gives
Remark (what arbitrary truncation does not gain).
Whenever
A nonintegral value need not lie in either signed interval of
Proposition 5.1.
To certify (4),
suppose
We retain the signed numerator: reduction modulo
Here
Further consequences and questions
We can place the interval in Proposition 1.1 inside
Thus rational and irrational targets remain available arbitrarily close
to
Nonperiodic coefficients
Rationality forces eventual periodicity of the binary digits obtained after carrying, not of the original integer coefficients. For example,
Its coefficients are unbounded and its first coefficient is
The coefficients increase
strictly and
Proposition 6.1 (prime gaps do not become periodic).
For every positive
Proof. If the gaps were eventually periodic, they would be
bounded. For each
The results on bounded prime gaps [13], clusters of each fixed size [11][20], and
extreme large gaps [4]
do not give the simultaneous inequalities in (4). This remains so
with Polymath’s bound
Verification and reproducibility
The linked Lean declarations use Lean 4 [9] and mathlib [10]. The formal proof of Proposition 1.1 changes
one coordinate at each stage, whereas the proof here uses triples. Both
choose the set containing the supports, the interval and the congruence
cutoffs before the value of the sum. For Corollary 3.1, the formal
statement covers every
Acknowledgements
The author received no external funding and declares no competing interests. The numbering follows Bloom’s catalogue [14].
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