Plectis

Short paper

Hankel Determinants of Geometric Moments and Rational Lambert Values

Summary. Positive geometric moments and a uniform partition-sum bound give the fixed-base asymptotic of Zudilin’s normalised Hankel determinants, including its constant and power correction. A separate calculation of degrees after cancellation in his 2004 forms extends the rational-base irrationality region. It includes every positive integral power of 31/4 and excludes 3/2.

This paper covers the fixed-base Hankel asymptotic and rational-base irrationality theorem; the long paper develops exact orders, content and endpoint obstructions, and the remaining problem at 3/2.

It does not establish the validity of claims tagged Lean, which belongs to the cited kernel-checked source, or a solution to Erdős #1049, which remains open.

In this paper

Introduction

Fix q∈(0,1). Write (z;q)m=∏j=0m−1(1−zqj) and F(t)=∑n≥1(tn−1)−1 for t>1. At the auxiliary parameters x=z=1, the normalisation in [5] gives

(1)vm∗(q)=∑t≥0q(m+1)t(q;q)m3(qt+1;q)m(qm+1+t;q)m+1,VN∗(q)=det(vi+j∗(q))0≤i,j<N.

The sums converge for 0<q<1. They also define formal series, since the tth summand has q-order (m+1)t.

Theorem 1.1 (the size of VN∗ at a fixed base). Fix 0<q<1 and write P=(q;q)∞, BN=N(N−1)(2N−1)/6 and CN=(N!)2(N+1)!/2N. There is a K(q)>0 with

VN∗(q)∼K(q)CNqBNP2NN−8F(1/q)(N→∞).

The constant K(q) is the convergent product in (13). Zudilin proved ordq⁡VN∗≥BN and the estimate |VN∗|≤qN3/3exp⁡(Oq(N2)) [5]. Theorem 1.1 determines the factorial, exponential and power factors contained in this estimate. We also recover the exact first formal term CNqBN. The formal calculation fixes N and expands at q=0; the asymptotic fixes q and lets N grow. Neither limit can be substituted for the other: multiplication by (1−q)N3 preserves the first formal term but changes the fixed-base logarithm by a cubic quantity. No uniformity as q→1 is asserted.

The proof compares the moments with constant-weight geometric moments. We write vm∗=∑k≥0akq(m+1)k with ak>0: the measure has mass akqk at qk. Heine’s identity expresses the determinant as a positive sum of squared Vandermondes over choices of N nodes [7]. The first N nodes normalise this sum but do not exhaust it; moving the last node gives a comparable contribution. Partitions encode all such displacements. For each fixed partition, only finitely many weight ratios change, at indices tending to infinity, so those ratios tend to 1. A summable bound independent of N then makes the whole normalised sum asymptotically independent of the weights. Cauchy’s determinant formula evaluates its limit in the constant-weight case.

The weights retain a different contribution. Their factorisation involves two-fold and three-fold convolutions of 1/(q;q)k, with relative corrections −2F(1/q)/(k+1) and −6F(1/q)/(k+2). In the logarithm of the weight product these give a harmonic sum, hence N−8F(1/q); the summable errors affect only the constant. Theorem 2.1 separates the determinant argument from this calculation and also treats entries (1−qi+j+1)−2.

Chowla’s conjecture, recorded by Erdős [1], asks whether F(t) is irrational for every rational t>1. This is a related arithmetic question, and the fixed-base asymptotic alone does not answer it. In Section 4 we instead specialise the polynomial forms of Zudilin’s 2004 construction [4]. They prove irrationality for coprime a>b≥1 satisfying

log⁡blog⁡a<θ∗=0.4056830213840605…,

where (15) defines θ∗ exactly. The constants are inherited from Zudilin; the degree calculation after polynomial cancellation supplies the rational-base estimate. The resulting region includes every positive integral power of 31/4, which lies outside the earlier sufficient region of Bundschuh and Väänänen [2]. Neither argument here settles 3/2.

Sections 2–3 prove Theorem 1.1; Section 4 gives the independent arithmetic argument. Section 5 links further questions to the companion. All logarithms are natural, empty products and determinants equal 1, and constants in Oq(⋅) may depend on the fixed q.

Geometric moment determinants

For constant weights, the moments are geometric series: Mm=∑k≥0q(m+1)k=(1−qm+1)−1. Cauchy’s determinant formula evaluates their determinant exactly. Writing

P=(q;q)∞,M(q)=∏d≥1(1−qd)−d,BN=∑j<Nj2,

we obtain

(2)DN(0):=det(11−qi+j+1)0≤i,j<N=qBNΔN∏0≤i,j<N(1−qi+j+1),ΔN=∏d=1N−1(1−qd)2(N−d).

For each fixed d, the multiplicity of 1−qd in the denominator increases to d, giving the factor M(q) in the limit. The numerator supplies two more copies:

ΔNP2N=∏d<N(1−qd)−2d∏d≥N(1−qd)−2N⟶M(q)2.

Indeed, ∑d|log⁡(1−qd)|<∞, and the logarithm of the second product is Oq(NqN). Thus

(3)DN(0)∼M(q)3qBNP2N.

Replacing the constant weights by ak will contribute ∏k<Nak. The two hypotheses below do different jobs: the ratio limit handles each fixed displacement; the polynomial bound permits summation over all displacements.

Theorem 2.1 (geometric moment determinants). Let 0<q<1 and ak>0 for k≥0. Suppose that, for fixed constants C>0 and κ≥0,

(4)ak+hak⟶1(k→∞) for each fixed h≥0,ak+hak≤C(1+h)κ(k,h≥0).

For Mm=∑k≥0akq(m+1)k and DN=det(Mi+j)0≤i,j<N, we have

(5)DN∼M(q)3qBNP2N∏k=0N−1ak(N→∞).

For every real s, the weights ak=(k+1)s satisfy (4) with C=1 and κ=max(s,0), and their first N terms have product (N!)s. Taking s=1 and summing the moments gives

(6)det(1(1−qi+j+1)2)0≤i,j<N∼M(q)3N!qBNP2N.

The polynomial bound excludes ak=ek, although its adjacent ratio tends to 1. The companion’s ordinary ratio-limit argument allows ak+1/ak→ρ∈(0,q−1) and, at ρ=1, gives (5) without that bound. This broader claim remains unformalised and is not used here: the theorem and its applications retain both hypotheses in (4).

Proof of Theorem 2.1. The bound ah≤Ca0(1+h)κ makes ∑k≥0akqkδqk a finite positive measure with moments Mm. Apply Cauchy–Binet to its finite truncations. The entries, hence the determinants, converge; the nonnegative tuple sums increase. Passing to the limit gives

(7)DN=∑0≤k0<⋯<kN−1∏i<Nakiqki∏i<j<N(qki−qkj)2.

The tuple ki=i contributes qBNΔN∏i<Nai. It does not account for the whole asymptotic. For example, replace (0,1,…,N−2,N−1) by (0,1,…,N−2,N). The ratio of its contribution to that of the original tuple is

(8)qaNaN−1∏d=1N−1(1−qd+11−qd)2=qaNaN−1(1−qN1−q)2⟶q(1−q)2.

Only pairs involving the moved node change, and their product telescopes. At q=1/2 the displaced tuple is asymptotically twice as large as the normalising tuple.

Subtracting (0,1,…,N−1) gives the shifts λi=ki−i. Since ki+1≥ki+1, these are nonnegative and weakly increasing; reversing their order gives a partition. For N=4, for example,

(0,1,3,5)⏟(ki)⟼(0,0,1,2)⏟(λi)⟼(2,1,0,0)⏟(μj).

In general, put μj=λN−j for 1≤j≤N, so that μ1≥⋯≥μN≥0. Division by the contribution of ki=i turns the summand for this tuple into

(9)WN(μ)=q∑j≤N(2j−1)μj∏j≤NaN−j+μjaN−j⋅∏1≤j<k≤N(1−qk−j+μj−μk1−qk−j)2.

The jth index from the right enters once through the mass qki and twice through each of its j−1 pairs with later indices. This gives the exponent 1+2(j−1)=2j−1. “Right” refers to increasing indices, not to the nodes qki, which decrease towards zero.

Set WN(μ)=0 for partitions with more than N positive parts, giving every sum the same index set. A fixed partition with ℓ positive parts affects only the last ℓ indices of (0,1,…,N−1). These indices tend to infinity while their displacements stay fixed, so the weight ratios in (9) tend to 1.

The Vandermonde quotient still contains a growing number of factors, but its dependence on N telescopes. The factors with j<k≤ℓ are fixed, and those with j>ℓ equal 1. For N≥ℓ and each j≤ℓ, the remaining factors satisfy

(10)∏k=ℓ+1N1−qk−j+μj1−qk−j=(qN+1−j;q)μj(qℓ+1−j;q)μj⟶1(qℓ+1−j;q)μj.

Thus each WN(μ) has the same limit as for constant weights.

The fixed-partition limit does not yet control partitions whose length or parts grow with N. For a uniform bound, group the Vandermonde factors by j. Only j≤ℓ contribute; each group’s denominator product is at least P and its numerator product at most 1. The polynomial shift bound therefore gives

WN(μ)≤(CP−2)ℓ∏j=1ℓ(1+μj)κq(2j−1)μj.

Let A=∑u≥1(1+u)κqu−1<∞. Dropping the ordering of the positive parts, we obtain

∑ℓ(μ)=ℓsupNWN(μ)≤(CP−2)ℓ∏j=1ℓ∑u≥1(1+u)κq(2j−1)u≤(CP−2A)ℓqℓ2.

Here q(2j−1)u≤q2j−1qu−1 and 1+3+⋯+(2ℓ−1)=ℓ2. The size of each part is absorbed in A; their number is controlled by qℓ2, which dominates (CP−2A)ℓ. Thus the bound is summable over ℓ and independent of N.

Dominated convergence gives the same limit for ∑μWN(μ) as for ak=1. Equation (2) evaluates that limit as M(q), without a separate partition identity. Restoring the normalising tuple supplies the weight product and, through ΔN/P2N, the other two copies of M(q). Hence

DNDN(0)∏k<Nak⟶1.

Combining this limit with (3) proves the theorem. ◻

The weights of Zudilin’s moments

We apply Theorem 2.1 by collecting the dependence on m in (1) into the single variable w=qm+1. For this purpose, set

(11)Gq(w)=1(w;q)∞3∑t≥0wt(q;q)t(qtw2;q)∞(qtw;q)∞2,ak(q)=[wk]P4Gq(w).

The product identities (q;q)m=P/(qm+1;q)∞ and (qa;q)m=(qa;q)∞/(qa+m;q)∞ give

(12)vm∗=P4Gq(qm+1)=∑k≥0ak(q)q(m+1)k.

These identities hold formally in Z[[q,w]] and, for fixed 0<q<1, analytically for |w|<1. In the formal identity only finitely many t contribute to any w-coefficient. For the analytic identity, we use the absence of denominator zeros in that disc and the locally uniform bounds on the product tails. The factor wt then gives locally uniform convergence of the sum. The signs of the coefficients are not evident from this product. The finite factorisation below gives positive weights and a uniform shift bound. Its two convolutions then give the accuracy needed to multiply the first N weights.

Positive weights

For r≥1 and k≥0, set

Rk(r)(q)=∑n1+⋯+nr=k(q;q)k∏j=1r(q;q)nj,

over r nonnegative parts. These are the multivariate Rogers–Szegő polynomials at unit arguments, written as sums of Gaussian multinomial polynomials [19]. At q=0, every Gaussian multinomial equals 1, so they count weak compositions (zero parts are allowed), and

ck:=Rk(2)(0)Rk(3)(0)=(k+1)2(k+2)2,∏k<Nck=CN.

Proposition 3.1 (the positive moment weights). For every k≥0,

ak=P4Rk(2)Rk(3)(q;q)k.

At fixed 0<q<1 these weights satisfy

P5ck≤ak≤P−1ck,ak+hak≤P−6(1+h)3(k,h≥0).

Proof. We use the Gaussian binomial coefficients [nj]q=(q;q)n/((q;q)j(q;q)n−j) for 0≤j≤n, and put E(z)=(z;q)∞−1. Euler’s expansion gives E(z)r=∑n≥0Rn(r)zn/(q;q)n. The desired factorisation multiplies two coefficients at the same index k, rather than taking a coefficient of E5. We obtain it by splitting k=n+j: the factor Rk(3) stays fixed, and summing the two factorial denominators supplies Rk(2). To produce this split, use the unnormalised q-difference operator ∂qf(z)=(f(z)−f(qz))/z. Since ∂qzj=(1−qj)zj−1, it cancels the last factor of (q;q)j and shifts the numerator index:

∂qE=E,∂qnE(z)3=∑j≥0Rn+j(3)(q;q)jzj.

The q-Leibniz rule, obtained by induction from the product rule, is

∂qn(fg)(z)=∑j=0n[nj]q(∂qjf)(qn−jz)(∂qn−jg)(z).

Let hk(z)=∑j=0k[kj]q(z;q)j. Applying the rule to E⋅E and using E(qmz)=(z;q)mE(z), we obtain ∂qkE(z)2=E(z)2hk(z) (for k=1, both sides equal E(z)2(2−z)). A second application, this time to E⋅E2, gives

∂qnE(z)3=E(z)3∑k=0n[nk]q(z;q)khk(z),

and hence

∑n≥0wn(q;q)n∂qnE(z)3=E(w)E(z)3∑k≥0wk(z;q)k(q;q)khk(z).

The left-hand side is ∑n,j≥0Rn+j(3)wnzj/((q;q)n(q;q)j). Putting z=w collects all pairs with the same sum n+j. The coefficient of wk is consequently Rk(3)∑j≤k((q;q)j(q;q)k−j)−1=Rk(2)Rk(3)/(q;q)k. On the right-hand side, put z=w, expand hk, and write k=j+t. The identity (w;q)j+t=(w;q)j(wqj;q)t gives

E(w)4∑j≥0wj(w;q)j2(q;q)j∑t≥0(wqj;q)t(q;q)twt.

The inner sum is evaluated by the q-binomial theorem:

∑t≥0(wqj;q)t(q;q)twt=(w2qj;q)∞(w;q)∞.

Finally, (w;q)j=(w;q)∞/(wqj;q)∞ cancels two of the five factors E(w), leaving

E(w)3∑j≥0wj(q;q)j(w2qj;q)∞(wqj;q)∞2=Gq(w).

We may read each identity coefficientwise, or as an absolutely convergent expansion when |z| and |w| are sufficiently small.

For the bounds, we write bk(r)=[zk](z;q)∞−r, so that Rk(r)=(q;q)kbk(r) and ak=P4(q;q)kbk(2)bk(3). By Euler’s expansion, bk(r) is an r-fold convolution of 1/(q;q)n, whose terms lie in [1,P−1]. There are (k+r−1r−1) compositions of k into r nonnegative parts, and we deduce

(k+r−1r−1)≤bk(r)≤P−r(k+r−1r−1).

Combining these at r=2,3 with P≤(q;q)k≤1 and ck=(k+1)(k+22) gives P5ck≤ak≤P−1ck. The shift bound follows from ck+h/ck≤(1+h)3. ◻

Positivity holds at each fixed real q∈(0,1), not coefficientwise in the formal q-series: a0(q)=P4=1−4q+O(q2). The bounds control shifted ratios, but do not determine the weight product. A relative error of order 1/k accumulates logarithmically; one of order 1/k2 is summable. Computing ak/ck to first order will therefore determine the power of N and give the fixed-shift limit.

The coefficient asymptotic

Proof of Theorem 1.1. Put L=F(1/q), ek=(q;q)k−1 and E=P−1. Replacing every ek by E gives E2(k+1) and E3(k+22), counting nonnegative pairs and triples with sum k. Terms with one deficit E−ei give the first correction. That coordinate has two possible positions in a pair and three in a triple; fixing it at i leaves one pair or k−i+1 triples. Thus the same total deficit produces a constant correction in the first convolution and a linear correction in the second. We calculate it and control its first moment.

Writing dk=E−ek, the identity ek+1−ek=qk+1ek+1 gives

dk=∑j>kqjej,0≤dk≤Eqk+11−q.

Thus ∑dk and ∑kdk converge. To evaluate the former, use Euler’s identity E(z)=∑k≥0ekzk=(z;q)∞−1 for |z|<1. Tonelli’s theorem and logarithmic differentiation at z=q give

S:=∑k≥0dk=∑j≥1jqjej=qE′(q)=E∑r≥1qr1−qr=EL.

In the double sum, qjej occurs once for each k=0,…,j−1, which explains the factor j. Logarithmic differentiation is justified by locally uniform convergence on |z|<1.

Let bk(r)=[zk]E(z)r. The finite-sum formula in Proposition 3.1 becomes

ak=P4(q;q)kbk(2)bk(3).

We expand each finite convolution using ek=E−dk. For two factors,

bk(2)=E2(k+1)−2E∑i=0kdi+∑i=0kdidk−i=E2(k+1−2L)+Oq((k+1)qk).

For three factors, the terms with one di contribute −3E2∑i=0k(k−i+1)di. Here the sum equals (k+1)S+Oq(1) because ∑idi<∞. Terms with two di are bounded by 3ES2, and the term with three is Oq((k+1)2qk). It follows that

bk(3)=E3((k+22)−3L(k+1))+Oq(1).

Division by (k+22) turns −3L(k+1) into the relative correction −6L/(k+2); the two-fold sum gives −2L/(k+1). Since (q;q)k=P(1+Oq(qk)), the leading constants in ak cancel: P5E5=1. Replacing (k+2)−1 by (k+1)−1 costs only Oq((k+1)−2). The two corrections therefore add, and with ck=(k+1)2(k+2)/2 we obtain

akck=(1−2Lk+1+Oq(qk))(1−6Lk+2+Oq((k+1)−2))(1+Oq(qk))=1−8Lk+1+Oq((k+1)−2).

In particular ak+1/ak→1, and multiplication of finitely many adjacent ratios gives ak+h/ak→1 for each fixed h. The uniform shift bound follows from Proposition 3.1, so Theorem 2.1 applies.

Let γE denote Euler’s constant and put

(13)A(q)=e−8γEL∏k≥0(akcke8L/(k+1)),K(q)=A(q)M(q)3.

For sufficiently large k, log⁡(1+u)=u+O(u2) gives log⁡(ak/ck)+8L/(k+1)=Oq((k+1)−2). This tail is summable, and the finitely many initial factors are positive by Proposition 3.1. Thus 0<A(q)<∞. Using ∏k<Nck=CN, separate the harmonic sum from this convergent remainder:

log⁡∏k<NakCN=−8L∑k<N1k+1+∑k<N(log⁡akck+8Lk+1).

The second sum tends to log⁡A(q)+8γEL. Using ∑k<N(k+1)−1=log⁡N+γE+o(1), the Euler-constant terms cancel, giving ∏k<Nak∼A(q)CNN−8L. Substitution in (5) proves the theorem, or equivalently

log⁡VN∗=BNlog⁡q+log⁡CN+2Nlog⁡P−8Llog⁡N+log⁡K(q)+o(1).

◻

The scales are now separate: the node geometry gives the cubic term BNlog⁡q; the cubic growth of the weights gives log⁡CN of order Nlog⁡N; their first relative correction gives −8F(1/q)log⁡N. The other terms are linear and constant. In particular, the power correction does not change the cubic rate.

The first nonzero formal term

The order of a nonzero formal series is the least exponent with nonzero coefficient. We now fix N and determine the first term in the formal q-expansion. The shifted term in (8) then has an extra factor of q. More generally, every nonempty partition has positive displacement exponent. Thus a single tuple determines the first formal term, although all partitions were needed for the fixed-base constant.

Theorem 3.2 (the first nonzero term of the Hankel determinant). For every N≥1,

ordq⁡VN∗=N(N−1)(2N−1)6,

and the coefficient of the first nonzero monomial is

[qN(N−1)(2N−1)/6]VN∗=(N!)2(N+1)!2N.

Proof. At q=0, the t=0 term of Gq(w) is (1−w2)/(1−w)5, while the remaining terms sum to w/(1−w)4. Thus

G0(w)=1+2w(1−w)4,ak(0)=ck>0.

We compute modulo qM+1 by truncating each moment sum in (12) at k=M. Since all omitted terms are divisible by qM+1, multilinearity leaves the determinant unchanged modulo that power. Applying finite Cauchy–Binet and then allowing M to increase, we obtain the coefficientwise identity

VN∗=∑k0<⋯<kN−1(∏i<Naki(q)qki)∏i<j<N(qki−qkj)2.

The order of the summand indexed by (ki) is ∑i<N(2N−1−2i)ki. Because ki≥i and all the weights 2N−1−2i are positive, we obtain the unique minimum at ki=i, with order and coefficient

∑i<N(2N−1−2i)i=BN,∏i<Nci=CN.

No other tuple has this order, so no coefficient from another tuple can cancel it. This argument needs the positive constant terms ak(0)=ck, not nonnegativity of all their formal coefficients. For N=2, the pair (0,1) contributes 6q+O(q2), and every other increasing pair has order at least two. ◻

This proves equality in Zudilin’s bound [5]. An alternative argument, which computes the first nonzero term of every transformed row, is given in the companion paper.

Rational bases

We now use the 2004 coefficient family. For U,V∈Z[X] of degree at most W, multiplying U(a/b) and V(a/b) by bW makes them integers. This is a sufficient clearing factor, not in general the smallest one. Cancelling a common nonconstant polynomial factor first lowers the degree bound. For example, at 3/2 the pair (X+1)(X+2),(X+1)(X+3) gives (35,45) after clearing to degree 2. After cancelling X+1, clearing to degree 1 gives (7,9). For Zudilin’s forms, let Kn be the original coefficient degree and Wn its degree after cancellation; both grow quadratically with n. The uncancelled remainder stays between positive constants. The normalising multiplier creates the decay, with leading scale x−(Kn−Wn) at fixed x>1. Clearing at x=a/b then gives

(14)bWn(a/b)−(Kn−Wn)=bKnaKn−Wn.

Net degree removal is therefore measured in powers of a, while the original degree costs powers of b. The remaining logarithmic terms are o(n2), so Kn/n2→C1 and (Kn−Wn)/n2→C0 give C1log⁡b<C0log⁡a. The proof must establish both the degree estimates and cancellation in Z[X], before evaluation.

We use the parameter direction from Zudilin’s construction [4], together with its thirteen intervals and constants C1,C0. At integer bases his theorem gives the irrationality-exponent bound C1/C0=2.46497868… [4]. Let ψ1(u)=∑k≥0(k+u)−2 for u>0, and let I consist of the thirteen intervals listed in the proof. We put

(15)C1=10912,J=∑[u,v)∈I(ψ1(u)−ψ1(v)),C0=266−3π2(225−J).

The intervals are disjoint and lie in [1/14,1), so 0≤J≤ψ1(1/14)−ψ1(1)<196. Together with π>3, these bounds give 0<C0<266<C1/2. Thus θ∗=C0/C1 and μ=C1/C0 are positive reciprocal constants. The notation μirr(ξ) instead denotes the irrationality exponent of a value. The estimates below give a sufficient cutoff; its optimality is unknown.

Theorem 4.1 (rational-base region for Zudilin’s forms). Let a>b≥1 be coprime integers with

bμ<a,equivalentlylog⁡blog⁡a<θ∗,θ∗=C0C1=0.4056830213840605…,μ=C1C0=2.4649786835749750….

Then F(a/b) is irrational.

Every integer base qualifies, since b=1 gives log⁡b/log⁡a=0. For each fixed b>1, the restriction a>b2.46497868… is much stronger than a>b, but still admits infinitely many coprime numerators. It includes 31/4 and its positive integral powers, whose logarithmic ratio is unchanged. It excludes 3/2, since θ∗<1/2<log⁡2/log⁡3. At equality the quadratic exponent vanishes and the estimates give no conclusion.

Proof of Theorem 4.1. The source forms and polynomial cancellation. Fix n≥1 and set

a0=14n+1,a1=12n+1,a2=14n+1,β=27n+2,N=15n.

In this proof N denotes the cyclotomic cutoff. We use the coefficient pair An,Bn of the source identities [4], with Hn=AnF−Bn. Let Φℓ be the cyclotomic polynomial whose roots are the primitive ℓth roots of unity. Put DN(X)=∏ℓ=1NΦℓ(X), Mn=266n2+34n+1, and

Ωn(X)=∏ℓ=2NΦℓ(X)νℓ,νℓ=ω(n/ℓ),

where the periodic function

ω(x)=max{0, ⌊14x⌋+⌊13x⌋−⌊12x⌋−⌊15x⌋, 2⌊14x⌋−⌊13x⌋−⌊15x⌋}

has period 1: the coefficients of the floor arguments in each difference have equal sums, 14+13=12+15 and 2⋅14=13+15. On [0,1) it is zero or one, with support

[1/14,1/12), [1/7,1/6), [3/14,1/4), [2/7,1/3),[5/14,2/5), [3/7,7/15), [1/2,8/15), [4/7,3/5),[9/14,2/3), [5/7,11/15), [11/14,4/5),[6/7,13/15), [13/14,14/15).

These are the intervals I used to define J. The function ω, these thirteen intervals and the exponents νℓ=ω(n/ℓ) of the source’s (22) are printed at [4].

First isolate the part that does not create decay. At x>1, put q=1/x. Identity (9) on p. 156 of the source gives

Hn(x)=∑t≥0qa0t(qt+1;q)a1−1(q;q)a1−1(q;q)β−a2−1(qa2+t;q)β−a2.

The denominator length is β−a2, as in the gamma expression (7) and residues (8) of [4]; the unnumbered display of R(T) on that page has length β−a2−1 instead. Each finite product lies in [P,1], where P=(q;q)∞>0. The t=0 term gives the lower bound; summing qa0t gives the upper bound:

P2≤Hn(x)≤P−21−qa0.

In particular Hn(x)>0 and log⁡Hn(x)=Ox(1).

The required polynomial integrality is the inclusion in Zudilin’s Lemma 7, display (23) [4]. Its comparison of cyclotomic valuations under six admissible parameter permutations gives divisibility in Z[X], not merely at integer values of X. Its parameter vector is n(13,14,12,14,15,13), its maximum is 15n, and β−a1−a2=n>0, which is the positivity condition s>0 of the lemma. The conditions (14) of [4], a1≤a2 and a1+a2≤β≤a0+a2, hold as well, so the exponent in (23) is the integer (16), which equals Mn. Lemma 7 therefore gives, for every n≥1,

Λn(X)=X−MnDN(X)Ωn(X)Hn(X)=Un(X)F(X)−Vn(X),Un,Vn∈Z[X].

This is the polynomial conclusion before integer specialisation in the source’s (24), p. 162. The coefficients are the cancelled source coefficients:

Un=X−Mn(DN/Ωn)An,Vn=X−Mn(DN/Ωn)Bn.

Indeed, coefficients of F and 1 over Q(X) are unique because F is not a rational function. To see this, we split F(eh) at m=1/h as h↓0. For m≤1/h, the inequalities y−1−1≤(ey−1)−1≤y−1 for 0<y≤1 give h−1∑m≤1/hm−1+O(h−1). Bounding the remaining terms by a geometric tail gives a further O(h−1), and therefore F(eh)=h−1log⁡(1/h)+O(h−1), which has no rational-function pole order at X=1. This establishes uniqueness of the coefficient functions; it assumes nothing about an individual value F(a/b). The cancelled remainder is positive for x>1, since DN/Ωn is a product of cyclotomic polynomials positive there.

The degrees after cancellation. The Gaussian binomial polynomial [mk]X=∏j=1k(1−Xm−k+j)/(1−Xj) is monic of degree k(m−k) for integers 0≤k≤m. The source’s (8) and (10) on p. 156 give the coefficient whose degree we need:

An(X)=∑k=a2β−1(−1)a1+a2+k+1Xa0k+(a12)−(β−a22)+(β−k2)[k−1a1−1]X[β−a2−1β−k−1]X.

Let dn,k be the degree of the kth summand. Adding the monomial exponent and the degrees of the two Gaussian factors gives

dn,k=a0k+(a12)−(β−a22)+(β−k2)+(a1−1)(k−a1)+(β−k−1)(k−a2)=−k2+80kn+3k−340n2−26n2.

Hence dn,k+1−dn,k=40n+1−k>0 for a2≤k≤β−2=27n. The last summand alone therefore determines the leading term, giving

Kn:=deg⁡An=1091n2+81n+22,Wn:=deg⁡Un=Kn−Mn+∑ℓ≤15n(1−νℓ)φ(ℓ).

Here φ(ℓ)=deg⁡Φℓ is Euler’s totient function, and ν1=ω(n)=0. In particular,

Kn−Wn=Mn−deg⁡(DN/Ωn).

The monomial removes Mn degrees and the surviving cyclotomic product restores deg⁡(DN/Ωn); their difference is the net removal Kn−Wn.

To determine the other coefficient’s degree, fix n and let x→∞. The bounds for Hn are uniform for x≥2, since P≥∏j≥1(1−2−j)>0 and (1−x−a0)−1≤2. Hence Hn(x)=O(1) and Λn(x)=O(xWn−Kn). The unique top summand of An has leading coefficient (−1)a1+a2+β=(−1)n. Since the Gaussian factors and DN/Ωn are monic, Un has that leading coefficient too. Moreover F(x)=x−1+O(x−2) and Kn≥2, so

Vn(x)=Un(x)F(x)−Λn(x)=(−1)nxWn−1+O(xWn−2).

Here Wn≥Kn−Mn=(559n2+13n)/2>0. Thus deg⁡Vn=Wn−1, with the same unit leading coefficient as Un. For every prime p∣b, reduction of the cleared first coordinate gives

bWnUn(a/b)≡(−1)naWn≢0(modp).

Thus Un(a/b) has reduced denominator exactly bWn, which is the least common clearing denominator for the pair. Any common integer divisor of the cleared pair is coprime to b. This exact cost concerns these coefficients only: common factors at other primes and combinations of rows remain separate questions.

The quadratic degree limits. We now keep the base fixed and let n→∞, extracting the quadratic part of the net degree removal. These are the cyclotomic limits of [4]. We use the reciprocal intervals, summatory totient estimate and trigamma function from [3], truncating the block sum before passing to the limit. The elementary summatory estimate ∑ℓ≤yφ(ℓ)=3y2/π2+O(ylog⁡y) gives

1n2∑ℓ≤15nφ(ℓ)⟶675π2.

For [u,v)∈I, the condition {n/ℓ}∈[u,v) is the disjoint union of intervals n/(k+v)<ℓ≤n/(k+u) for k≥0. Apply the summatory estimate to finitely many blocks. Instead of summing its errors over all k, bound the omitted blocks together: for k≥K≥1, all their indices satisfy ℓ≤n/(K+u). The bound ∑ℓ≤yφ(ℓ)≤y2 gives

1n2∑ℓ≤n/(K+u)φ(ℓ)≤1(K+u)2.

For y≥1, sum φ(ℓ)≤ℓ; for 0≤y<1 the sum is empty. The tail bound is uniform in n, so we may let n and then K tend to infinity:

1n2∑ℓ≤15nνℓφ(ℓ)⟶3π2∑[u,v)∈I∑k≥0(1(k+u)2−1(k+v)2)=3Jπ2.

Here no contributing index exceeds 14n, since u≥1/14. Consequently

Kn/n2⟶C1,(Kn−Wn)/n2⟶C0.

The cleared remainder. It remains to turn polynomial degrees into values at fixed x>1. Writing μMob for the Möbius function, we have

log⁡Φℓ(x)−φ(ℓ)log⁡x=∑d∣ℓμMob(d)log⁡(1−x−ℓ/d).

Each −log⁡(1−x−d) occurs only for multiples ℓ of d, at most 15n/d times. The total absolute error is therefore at most

15n∑d≥1−log⁡(1−x−d)d.

The series converges because −log⁡(1−x−d)≤x−d/(1−x−1), so the error is Ox(n). Using 0≤1−νℓ≤1 and log⁡Hn(x)=Ox(1) gives

log⁡Λn(x)=−(Kn−Wn)log⁡x+Ox(n).

At x=a/b, the coefficients bWnUn(a/b) and bWnVn(a/b) are integers, and

log⁡(bWnΛn(a/b))=Knlog⁡b−(Kn−Wn)log⁡a+Oa/b(n)=(C1log⁡b−C0log⁡a)n2+o(n2).

The quadratic coefficient is negative under the hypothesis. If F(a/b)=r/s with integers r,s and s>0, then sbWnΛn(a/b) would be a positive integer tending to zero. This contradiction uses positivity of the same remainder, not independence of successive forms. ◻

Corollary 4.2. F((31/4)r) is irrational for every integer r≥1.

Proof. The exact inequalities 312<45 and 4200<3181 give 2/5<log⁡4/log⁡31<81/200. The first term of each trigamma difference yields

J≥∑[u,v)∈I(u−2−v−2)=201564069025125971865920.

Using π>157/50 gives the rational lower bound

θ∗>23596300095232635820307922172744>81200.

Taking a common positive integer power preserves both the logarithmic ratio and coprimality, so the same criterion applies for every r≥1. ◻

Corollary 4.3 (an irrationality measure uniform over powers). For coprime a>b≥1 with θ=log⁡b/log⁡a<θ∗ and every integer r≥1,

μirr(F((a/b)r))≤1−θθ∗−θ.

Here μirr(ξ) is the supremum of the exponents ν for which |ξ−p/q|<q−ν has infinitely many reduced rational solutions. In particular, μirr(F((31/4)r))<301 for every r≥1.

Proof. We use Zudilin’s passage from linear forms to an exponent bound [4], at each fixed base (a/b)r. Take Un,Vn and Wn=deg⁡Un from Theorem 4.1. A measure needs more than positive remainders tending to zero: it must bound how small they are relative to their coefficients. The logarithmic remainder asymptotic supplies a lower bound; we now bound Un above. In that construction the coefficient of F before cancellation is a sum of O(n) Laurent monomials times two Gaussian binomial polynomials. Each Gaussian polynomial has nonnegative coefficients summing to at most 227n+2. Thus the sum of the absolute coefficients is exp⁡(O(n)). Its largest exponent is Kn=(1091n2+81n+2)/2, so its absolute value at a fixed x>1 is at most xKnexp⁡(O(n)). The cyclotomic estimate in the same proof bounds the normalising multiplier by xWn−Knexp⁡(Ox(n)). Multiplication gives

|Un(x)|≤xWnexp⁡(Ox(n))(x>1 fixed).

Set ξ=F(a/b), Qn=bWnUn(a/b) and Pn=bWnVn(a/b). With

α=(C1−C0)log⁡a,τ=C0log⁡a−C1log⁡b>0,

we have log⁡(Qnξ−Pn)=−τn2+o(n2) and |Qn|≤exp⁡(αn2+o(n2)).

Here q denotes an approximation denominator, not the geometric base of Sections 2 and 3. The comparison uses the integer Ap−Bq, allowing it to vanish. For integers A,B,p,q with q>0, if L=Aξ−B and 2q|L|≤1, then

|L|≤|A||ξ−p/q|.

If Ap−Bq=0, this is equality; otherwise 1/q≤|L|+|A||ξ−p/q| gives the inequality. Thus no rational p/q is excluded from the comparison. Fix 0<η<τ and write

e−(τ+η)n2≤Qnξ−Pn≤e−(τ−η)n2,|Qn|≤e(α+η)n2

for all sufficiently large n. The upper remainder bound determines our choice: for a sufficiently large denominator q, take n=⌈log⁡(2q)/(τ−η)⌉. Then 2q(Qnξ−Pn)≤1. The preceding integer argument now applies to (A,B)=(Qn,Pn) for every numerator p. Also Qn≠0: otherwise Qnξ−Pn would be an integer strictly between 0 and 1. The lower remainder bound and the coefficient bound now give

|ξ−p/q|≥e−(α+τ+2η)n2=q−(α+τ+2η)/(τ−η)−o(1),

since n2=log⁡(2q)/(τ−η)+Oη(log⁡q+1). The rounding error is o(log⁡q), so it does not change the exponent. This choice covers every sufficiently large approximation denominator q; no monotonicity assumption on the coefficients Qn is used.

Letting η↓0, we deduce the bound 1+α/τ=(1−θ)/(θ∗−θ). A common power multiplies α and τ by r, so the quotient is unchanged, although the constants in the approximation inequality may depend on r. For 31/4, the exact interval bounds in the companion record, Section 2.5, give θ<0.4036982 and θ∗>0.40568. The quotient increases with θ and decreases with θ∗ in this range, so

1−θθ∗−θ<1−0.40369820.40568−0.4036982=29815099909<301.

The same section gives the rational certificates for these bounds and sharper enclosures of the constants. ◻

Comparison with earlier criteria

Bundschuh and Väänänen’s Theorem 2 at α=−1 [2] gives irrationality for log⁡b/log⁡a<θBV:=1/2−1/π2. Their q is the base a/b>1, not its reciprocal. Their logarithmic derivative is Lq(z)=∑j≥1(qj+z)−1, so the value at z=α=−1 is exactly F(a/b). The rational height is h(q)=a, and their parameter λ=log⁡h(q)/log⁡q is 1/(1−log⁡b/log⁡a), which gives the displayed cutoff. Since π2<10, one has θBV<2/5<log⁡4/log⁡31, so 31/4 lies outside that sufficient region. The two sufficient regions differ on [θBV,θ∗). Zudilin also notes an extension to noninteger rational bases p=r/s for the generalized q-logarithm when log⁡|r|>clog⁡|s|, with c>0 computable but unspecified [5]. The value c=μ here comes from the 2004 forms [4], not from evaluating the unspecified constant in the 2016 construction.

The positive-remainder estimates require x>1, so they give no statement for negative bases. The series diverges at x=1. The companion’s height-criterion section also applies Bundschuh and Väänänen’s cited theorem at 7/2.

Further questions

The determinant asymptotic still needs a coefficient-denominator estimate to give an integer contradiction. The companion’s rational-value model has the same formal orders, leading coefficients and type of fixed-base power correction, but a rational target value. Its denominator calculation shows why clearing need not yield small nonzero integer forms. The model and its denominator argument have ordinary proofs only and are not used above.

The approximants’ polynomial coefficients pose a separate moment problem. The normalisation matters in Van Assche’s little-q-Legendre construction [12] and the multiple-orthogonality construction of Postelmans and Van Assche [13]. In the 2016 family, the companion paper proves positivity of the first matrix of a coefficient pencil for sizes N≤8, with real, interlacing roots below F(p) for p>1. The shifted minors and coefficientwise positivity are supported by the stated finite polynomial computations. The coefficient-moment section gives the definitions and the precise ranges. Positivity for every N and convergence of the largest root remain open. The general moment criteria of Wang and Zhu [15] and Sokal and Walrad [17], Berg’s factorial-power example [16], and the quadrature construction of Golub and Welsch [18] provide the relevant comparisons. Using a recurrence from another family would require a proof that it holds for these coefficients. The root-of-unity method of Krattenthaler, Rochev, Väänänen and Zudilin [14], for example, concerns a separate construction.

Congruences and divided forms

For Q∈Z[X] of degree at most W, the homogenised value HW(Q)=2WQ(3/2) is integral. The companion treats its congruences at powers of 2 and 3, including integer rescaling and endpoint congruences and signed sums, with the rank-one case. Smith normal form counts the residue image [6]. To obtain a small nonzero remainder after division, the count must also distinguish nearby real values from repeated ones.

Let M integral rows (Aj,Bj) have remainders ej=AjF(3/2)−Bj, and let D be a positive integer. Suppose the subset sums ∑j∈I(Aj,Bj) take Q values in (Z/DZ)2, with at most k subsets giving any fixed real remainder within a residue class. Put T=∑j|ej|. The least and greatest subset remainders are

∑ej<0ejand∑ej>0ej;

their difference is T. For a positive integer n, divide this whole range into half-open intervals of width D/n, starting at its least value. At most ⌊nT/D⌋+1 intervals suffice, including a last interval when the greatest value is an endpoint. If every residue–interval pair contained only one remainder value, it would contain at most k subsets. Hence

(16)2M>Qk(⌊nTD⌋+1)

forces two different remainders in one residue–interval pair. Subtracting the subset sums and dividing by D gives an integral linear form of nonzero absolute value less than 1/n: the residue condition gives integrality, the interval gives smallness, and the multiplicity bound prevents a zero difference. The quantitative lemma and its proof state the finite-set result independently of Lambert series. Distinct input rows do not rule out equal subset remainders; k bounds repetitions within a residue class. No family of bounds on Q,T,k satisfying (16) for arbitrarily large n at 3/2 is supplied here.

The elementary integer-base method provides a different comparison. Vandehey [10] and Duverney and Tachiya [11] use integer-base expansions. At a noninteger rational base the cleared-tail recurrence has a growing denominator contribution. The clearing and tail-recurrence calculations in the companion paper include the coordinatewise obstruction at 3/2. They make no assertion about other approximation families. At the function level, Bell and Smertnig [9] exclude Mahler equations for the divisor generating series, while leaving the arithmetic of a single rational argument undecided.

A construction problem.

The unrestricted request for primitive polynomial rows and a signed combination with divided remainder strictly between 0 and 1/n is equivalent to irrationality of the target; the companion’s section on divided linear forms states and proves the equivalence. A more specific problem must prescribe a family: for the 2004 forms, the question is whether a parameter direction improves θ∗. The all-base degree restriction bounds the degree cutoff by 1/2. It assumes one polynomial family, with common leading constants in its degree, coefficient-height and remainder estimates at every fixed real base x>1; errors may depend on x. A cutoff above 1/2 would make remainder decay outpace coefficient growth at a sufficiently large fixed integer base. Consecutive integer row determinants would then tend to zero and eventually vanish, forcing the rational row ratios to stabilise. The remainders would be either zero or bounded away from zero, contradicting nonzero decay. Estimates only at 3/2 do not permit that choice of base.

Under the same hypotheses, the nondecay corollary excludes decay of the denominator-cleared, undivided forms whenever b<a<b2, including 3/2, without assuming a quadratic degree limit. If that limit exists, their absolute values tend to infinity throughout this strict region. Further division by base-dependent content and families outside these hypotheses remain unclassified, as does equality in the cutoff of Section 4.

Verification and reproducibility

The evidence record lists Lean proofs for all seven numbered results and Comparator checks for six, with their checked revisions. Beside the main source revision, Theorem 2.1 uses the later geometric-moment proof; its Comparator association remains pending. Neither the broader ratio-limit argument nor the rational-value model is a dependency; both have ordinary proofs only. This expository revision changes no result statement and has no fresh Lean or Comparator run or independent review.

Data availability.

The cited source revision contains the Lean sources, toolchain and library manifest. The companion paper supplies the longer algebraic arguments and the precise scope of the finite computations.

Funding and competing interests.

This work received no external funding. The author declares no competing interests.

Acknowledgements.

The problem numbering follows the catalogue maintained by Thomas Bloom [8].

References

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