Plectis

Long paper

Running least common multiples: distinct values and multiplicities

Erdős #269 By July 2026; revised 5 October 2026 Authorship, AI use and citation

Summary. For the prime set {2,3,5}, a five-map argument proves irrationality of the sum over distinct running LCMs. Two-prime sums reduce to a transcendental Hecke–Mahler value. For the repeated three-prime sum, an equivalent residue criterion leaves an arithmetic condition open. Complete ordinary arguments for general distinct-running-LCM sums and prime-power subseries are retained as remarks awaiting formalisation.

This paper covers distinct-height irrationality, all-rank kernel structure and the repeated-sum tail criteria, preserving the multiplicity distinction and the remaining open residue-window obligation.

It does not establish the validity of claims tagged Lean, which belongs to the cited kernel-checked source, or a solution to Erdős #269, which remains open.

In this paper

Repeated tails and prime-power subseries

We compare the two normalisations before considering the sums over pure prime powers. The subseries assertions in this subsection have ordinary proofs and remain unformalised. For P={2,3,5} the two tail recurrences have the same bases, bτa=Pa+1/Pa=ba, but their coefficients behave differently:

Ya+1=baYa−μτa,Xa+1=baXa−ma.

The first identity is Remark 5.6(ii); the second is Theorem 8.2, with the notation of Section 8. The five types give only the coefficients 1,3,9,13, whereas the weighted block counts satisfy ma=Θ((a+1)2) by Lemma 8.3. Consequently Xa>ma/30 is unbounded. Under rationality the integral values BXa need not repeat, and the maps y↦(ma+y)/ba form an infinite family depending on a. Even equality of two tails would not identify their later coefficients. The residue criterion in Section 10 compares an endpoint residue with a quadratic bound instead. The example after Proposition 13.2 shows the limit of an argument using just bases and growth: the same bases admit quadratic numerators m^a with ∑am^a/Pa+1=9.

The two-tail proof of Remark 5.1 stops at the same place. Over the prime powers the repeated sum is RP=∑k≥0ck/Qk, where ck counts the smooth integers in [tk,tk+1), with t0=1. The two tails after tk and after tkpn still have words that differ by rearranging chains, and a rational value still makes the scaled tails integers of one denominator. But the scaled tails are unbounded, as the Xa are, and Remark 5.3 needs every tail in (0,1): the integer f(σi)−f(σi′) is shown to vanish because it equals a difference of two tails. With unbounded tails that step fails, the digits ck move with the rearrangement as well, and equality of two tails no longer forces agreement on each rearranged run. The irrationality of RP for |P|≥3 remains open.

Prime-power subseries.

The comparison of two tails applies to each prime-power subseries. For p∈P put

Ep=∑α≥01L⁡(pα)=∑α≥01HP⁡(pα),

the sub-sum of RP over the terms at which the smooth integer is a power of p. For P={p,q} with p<q these are the numbers A=Ep and 1+B∗=Eq of the proof of Theorem 1.2.

Remark 5.9 (sub-sums and the catalogue sum). Let P be a finite set of primes with |P|≥2.

  1. DP=∑q∈PEq−(|P|−1).

  2. If P={p,q}, then HP⁡(piqj)=HP⁡(pi)HP⁡(qj) for all i,j≥0, and RP=EpEq.

  3. If P={p,q,r}, then HP⁡(piqjrk)=HP⁡(pi)HP⁡(qj)HP⁡(rk)pκp(j,k)qκq(i,k)rκr(i,j), where κp(j,k)=⌊jlogp⁡q+klogp⁡r⌋−⌊jlogp⁡q⌋−⌊klogp⁡r⌋∈{0,1} and κq,κr are defined in the same way. For a general finite P the corresponding exponents lie in {0,…,|P|−2}.

Proof. (i) Each term 1/Qk of DP with k≥1 is a term of Eqk and of no other Eq, and each Eq also contains the term 1. (ii) and (iii) The exponent of p in HP⁡(∏q∈Pqeq) is ep+⌊∑q≠peqlogp⁡q⌋, and its exponent in ∏q∈PHP⁡(qeq) is ep+∑q≠p⌊eqlogp⁡q⌋. For m nonnegative reals the floor of the sum exceeds the sum of the floors by an integer in {0,…,m−1}. With two primes m=1, so the running LCMs factor, and summing HP⁡(pi)−1HP⁡(qj)−1 over i,j≥0 gives EpEq. ◻

With three primes RP is therefore the product of the three single-prime sums twisted by the carries κ, and the plain product EpEqEr differs from it.

Remark 5.10 (the single-prime sub-sums). Let P be a finite set of primes with |P|≥2 and let p∈P. Then Ep is irrational.

For P={p,q}, Ep is A or 1+B∗ in the proof of Theorem 1.2, an affine function of the Hecke–Mahler value Fθ(1/p,1/q) with nonzero slope; for p<q, Ep=p/(p−1)−(q−1)Fθ(1/p,1/q) by (6). It is transcendental by the theorem of Bugeaud and Laurent [15], in the case due to Loxton and van der Poorten [16]. We cite these sources for this case and have not re-verified its earlier attribution history.

Proof. We modify the word argument so that it counts only occurrences of p. For an infinite word u and a finite word σ=σ1⋯σn, put

Vp(u)=∑i:ui=p1u1⋯ui,fp(σ)=∑j:σj=pσj+1⋯σn.

Then Vp(σu)=(fp(σ)+Vp(u))/Π(σ). Writing yk=Vp(qk+1qk+2⋯), we have

Ep=1+∑k:qk=p1Qk,QkEp=Qk+∑j≤k, qj=pQkQj+yk.

In an actual suffix, the prefix product at the jth occurrence of p is at least pj, with strict inequality after another prime has occurred. Hence 0<Vp(u)<1/(p−1)≤1, and rationality Ep=N/K would imply Kyk∈Z. The proof of Remark 5.3 therefore applies to Vp,fp as well. On a chain of distinct primes containing p, only one term remains in fp: the product of the primes following p. Unique factorisation detects a change in that set, without recovering its order. This weaker requirement avoids the collisions of the full block numerator f.

For each q≠p, the form θp−θq is nonzero on the rational subspace L used in Section 5.1. We may therefore choose v∈L with |vq|≤1 for every q and vq≠vp for q≠p, where vq=θq(v), and put μ=minq≠p|vp−vq|>0. Suppose Ep=N/K. Choose a jump tk labelled p, and choose T,ν,g,β as in the general irrationality proof, with 2ν≥K. Set η=1/10 and first fix

0<ε<min{β,g/2,log⁡2/(2|P|),η/4,ημ/4}.

Dirichlet’s theorem then supplies arbitrarily large n and integers mq≥1 such that δp=0 and 0<|δq|=|nlog⁡p−mqlog⁡q|<ε for q≠p. We compare tk with tm=tkpn and cut crossings at gaps greater than 2ε. As before, each chain consists of distinct primes and is merely rearranged by the phase shift. The common prefix of ν letters and the integral-tail argument give yk=ym, and hence fp(C)=fp(C′) for every chain and its rearrangement.

We shall contradict this equality near the origin of T0. Put

b0=minq≠p|δq||vp−vq|,B={q≠p:δq<0},A+={q≠p:vq<vp},A−={q≠p:vq>vp}.

Since 0<b0≤ε/μ<η/4 and A+,A− partition the nonempty set P∖{p}, one of these two sets, say As with s∈{+1,−1}, differs from B. Take b=sb0/2 and consider z=bv+Θ(−η/2). For each q, its crossing nearest η/2 occurs at

τq=η/2−bvq∈(3η/8,5η/8),τq−τp=b(vp−vq).

Every other q-crossing lies outside (−η/4,5η/4), and for q≠p the displayed difference is nonzero with absolute value at most |δq|/2. We choose a neighbourhood U of z in T0 on which there are no crossings in [−η/4,η/4]∪[3η/4,5η/4], each prime has a crossing in (η/4,3η/4), and every difference τq−τp retains its sign and has absolute value less than |δq|. These conditions are open and hold strictly at z.

By density, θk+Θ(t∗)∈U for some t∗>T+2. The resulting crossings near t∗ form one chain: each is within ε of the p-crossing and every other crossing is more than η/2>2ε away. In this chain the followers of p form As. After the shift, q follows p precisely when τq−τp>δq, which, by the bound |τq−τp|<|δq|, is equivalent to δq<0. Its followers now form B≠As, contradicting fp(C)=fp(C′). ◻

This argument uses a change of followers and so needs no two-wall lemma. Either of A+,A− may be empty, but they are distinct when |P|≥2. For P={p} the sum is p/(p−1), and this is precisely where the choice of two distinct follower sets fails. The strict conditions defining U are needed to carry the construction to an actual orbit.

For P={2,3,5}, p=2, tk=220 and n=65, the first rearranged chain is (2,3) against (3,2) after 131 letters, with f2 equal to 3 and 1, and the difference of the two tails, computed exactly to 300 letters, has log10⁡|yk−ym|=−58.098.

For the repeated sum RP, changing the scale from tk to tkpn brings in early terms from the rays pαw, with w supported on P∖{p}. The comparison above accounts only for the ray w=1, so it gives no corresponding estimate for the difference of the full repeated tails. In the case P={2,3,5} those normalised tails are unbounded, as the lower bounds below show.

About this paper

Authorship and AI use. Will Cook built and directed the research infrastructure and maintains the public release. He reviewed claims when he could. AI agents did most of the research and drafting. Cook did not independently verify every claim.

Cite and contact. Cite this paper by its title, author and date above, with its PDF; cite the earlier sources it uses for a mathematical result. For software, use the release citation and give the commit used. Contact Will with questions or corrections.

Prefer the manuscript?

Equations typeset from the exact TeX. Rendered from the LaTeX manuscript source with file fingerprint sha256:27b68b4b0cf24ce2. Its file fingerprint matched the published source record, so the PDF above, the LaTeX, and this page are one manuscript. Redeploying the site regenerates this page from whatever the public repository holds at that moment.