Plectis

Long paper

Running least common multiples: distinct values and multiplicities

Erdős #269 By July 2026; revised 5 October 2026 Authorship, AI use and citation

Summary. For the prime set {2,3,5}, a five-map argument proves irrationality of the sum over distinct running LCMs. Two-prime sums reduce to a transcendental Hecke–Mahler value. For the repeated three-prime sum, an equivalent residue criterion leaves an arithmetic condition open. Complete ordinary arguments for general distinct-running-LCM sums and prime-power subseries are retained as remarks awaiting formalisation.

This paper covers distinct-height irrationality, all-rank kernel structure and the repeated-sum tail criteria, preserving the multiplicity distinction and the remaining open residue-window obligation.

It does not establish the validity of claims tagged Lean, which belongs to the cited kernel-checked source, or a solution to Erdős #269, which remains open.

In this paper

Words obtained from a linear flow

We apply the interchange argument to the order in which finitely many linear functions take integer values. Their slopes will be assumed linearly independent over Q; this hypothesis is not assumed for reciprocal prime logarithms. Interchanging two late crossings then determines the rational relations among the corresponding subseries, without requiring recovery of every letter. The arguments in this section remain ordinary proofs awaiting formalisation.

Let A be a finite alphabet. Give a∈A an integer radix ba≥2 and a rational coefficient ca. For w=w1w2⋯, define

Q0=1,Qn=∏j=1nbwj,Vc(w)=∑n≥1cwnQn,Ta(x)=ca+xba.

Write σw=w2w3⋯ and Xw={σnw:n≥0}― in the one-sided product topology. A word belongs to Xw precisely when each of its finite prefixes begins some shifted word. It need not itself be a shift. The first letter acts by the outermost map: if u=u1⋯um, then Vc(uz)=Tu1∘⋯∘Tum(Vc(z)). Put B(u)=∏j≤mbuj, with B(∅)=1.

Remark 6.1 (interchanging two letters after a long common prefix). Suppose Vc(w) is rational. If for distinct letters a,b and arbitrarily long words u there is a common infinite suffix z such that both uabz and ubaz belong to Xw, then

ca(bb−1)=cb(ba−1).

If such interchanges join every pair of letters along a connected graph, Vc(w) is rational precisely when there is λ∈Q with ca=λ(ba−1) for all a; in that case Vc(w)=λ.

Proof. First clear the common denominator of the coefficients, so that all ca are integers. The recurrence Vc(σw)=bw1Vc(w)−cw1 shows that, if Vc(w)=p/K, then every shifted value belongs to K−1Z. For λa=ca/(ba−1), the positive weights

bwn−1Qn=1Qn−1−1Qn

sum to one. Hence Vc(v) lies between minaλa and maxaλa for every word v. Sharing m initial letters changes a value by at most the width of this interval divided by B(u). Thus Vc is continuous. Since K−1Z is closed, the lattice condition passes from the actual shifts to all of Xw.

The order of the maps matters. A direct calculation gives, for every x,

Ta(Tb(x))−Tb(Ta(x))=ca(bb−1)−cb(ba−1)babb.

The values of uabz and ubaz therefore differ by this number divided by B(u). Their difference belongs to K−1Z. If its numerator were nonzero, its absolute value would be positive but smaller than 1/K for a sufficiently long u, a contradiction. On a connected interchange graph all λa agree. Conversely, for ca=λ(ba−1) the displayed positive weights telescope and give Vc(v)=λ for every v. Dividing by the earlier common denominator restores the statement for rational coefficients. ◻

The common suffix is essential: distinct words can have the same affine map. For example, the blocks (5,7,3,2) and (7,2,3,5) have the same map (51+x)/210. Choosing the second block at block indices 1,2,4,8,… produces a non-eventually-periodic word with rational value 51/209. Thus aperiodicity and bounded tails do not suffice, even with integer bases; the interchange hypothesis is essential to the argument. Nor does the lemma assert sufficiency when its graph is disconnected.

Now let r1,…,rd>0, d≥2, be linearly independent over Q. Record the letter i at each positive time t for which rit+θi∈Z, where θi∈[0,1). Assume that no two of these functions take integer values simultaneously at positive time. In chronological order, the crossings give an infinite word w on {1,…,d}.

Remark 6.2 (isolated interchanges in the crossing sequence). Every pair of distinct labels satisfies the late-interchange hypothesis of Remark 6.1 for Xw.

Proof. Fix a label a. Immediately after its sufficiently late crossings, the remaining coordinates of the flow are

θi−riraθa+krira(mod1)(i≠a),

where k runs through all sufficiently large integers. These points are dense in the (d−1)-torus. Indeed, 1 and the ri/ra for i≠a are rationally independent. For every nonzero integral character of the torus, its average along this orbit is a geometric sum divided by its length and tends to zero. Trigonometric approximation of continuous functions then shows that every nonempty open set is visited infinitely often. This also proves density after any finite initial segment is discarded.

Fix b≠a and an arbitrarily large integer L, and work on the section just after an a-crossing. Set T=L/ra and choose the phase of b so that the b-coordinate crosses at T. This phase is nonzero, since Lrb/ra∉Z. Choose the remaining phases outside the countable sets that cause a crossing at zero, a third crossing at T, or any other positive simultaneous crossing. The resulting singular configuration has exactly the one double crossing of a,b at T: a second meeting of these two coordinates would make rb/ra rational.

Perturb the b phase on opposite sides. On each bounded time interval, a sufficiently small perturbation changes only this pair’s order. Taking one-sided limits gives uabz and ubaz with the same infinite suffix z. No fixed nonzero perturbation is required to preserve all later crossings: agreement on each finite interval suffices for these limiting words. Their common prefix has at least L−1 letters, from the earlier a-crossings. For each finite prefix of either limit, a small open set of nonsingular section phases realises that prefix. The dense actual a-section orbit meets that set, so the prefix occurs at the beginning of an actual shifted word. Consequently both limiting words belong to Xw. Letting L grow proves the assertion. ◻

Remark 6.3 (rational relations among the subseries). Under the preceding hypotheses on the linear flow, choose integers bi≥2, put Qn=∏k≤nbwk and

Si=∑n:wn=i1Qn(1≤i≤d).

For every ci∈Q,

∑i=1dciSi∈Q⟺ci=λ(bi−1)for all i and some λ∈Q.

The rational value is λ. Equivalently, all rational relations a0+∑iaiSi=0 are multiples of (−1,b1−1,…,bd−1). Thus the span of 1,S1,…,Sd has dimension d; each Si and each nonempty proper unweighted sub-sum is irrational. The full unweighted sum is irrational exactly when the radices are not all equal.

The following argument proves the assertion of the remark in ordinary mathematics; formalisation and external peer review remain outstanding.

Proof. Absolute convergence gives ∑iciSi=Vc(w). The previous two remarks make the interchange graph complete, so they give both directions and the stated value. The relation space follows by moving the rational value to the constant coordinate. An indicator vector of a nonempty proper set has both zero and one entries and cannot be a multiple of the strictly positive vector (bi−1)i. The all-ones vector is such a multiple precisely when all the bi agree. ◻

For example, take

(r1,r2,r3,r4)=(1,2,3,6),(b1,b2,b3,b4)=(2,3,5,7),θi=0.

The four rates form the standard basis of the biquadratic field Q(2,3) over Q; the ratio of any two distinct rates is irrational, so positive crossings never coincide. Write (d1,d2,d3,d4)=(1,2,3,6). Counting crossings up to the nth crossing of the i-th coordinate gives the explicit series

(9)Si=∑n≥1(∏j=14bj⌊ndj/di⌋)−1.

The only rational relation among 1,S1,S2,S3,S4 is generated by S1+2S2+4S3+6S4=1. In particular their rational span has dimension four and ∑iSi is irrational. This does not provide an irrationality measure or transcendence result. In the related two-letter Hecke–Mahler setting, stronger transcendence results exist [15]; the example’s four independent rates do not satisfy that two-letter hypothesis. The ordinary two-wall argument for the distinct running-LCM sum avoids this assumption on reciprocal prime logarithms. The repeated running-LCM question remains open.

About this paper

Authorship and AI use. Will Cook built and directed the research infrastructure and maintains the public release. He reviewed claims when he could. AI agents did most of the research and drafting. Cook did not independently verify every claim.

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