Plectis

Long paper

Paths in Polynomial Lemniscates: A Degree-Seven Counterexample and Radial Connections

Summary. The record gives the rational estimates and geometric proof for ani's degree-seven polynomial: every connected set in its strict unit lemniscate joining two roots has Hausdorff measure greater than two. It develops contained paths for trinomials, collinear roots and two sparse families. Ordinary analytic arguments for critical-value criteria retain their unformalised inputs beside the statements. Critical-value moments, counterexamples to prescribed paths and questions about flow-strip geometry complete the account. The one-polynomial formal statement and correspondence with the historical wording remain distinct.

This paper covers the exact geometry of ani's one-polynomial counterexample, proved positive families and critical-value arguments with their unformalised inputs identified; formal-statement status and historical correspondence remain owned by the claims registry.

It does not establish the validity of claims tagged Lean, which belongs to the cited kernel-checked source, or the current status of Erdős #1041, including the later one-polynomial Formal Conjectures path-image Hausdorff-length check and its unreviewed historical curve-length correspondence; those distinctions belong to docs/claims.json in the mathematics repository.

In this paper

Degree three

For a cubic we can estimate the inverse roots directly after normalising at a critical point of least value modulus. The root-disc hypothesis makes that modulus less than one, and two radial segments in the normalised coordinates give a path shorter than 2.

Theorem 6.1 (the cubic case). Let f(z)=∏j=13(z−zj) with |zj|<1, the roots listed with multiplicity. Then two listed root occurrences are joined inside {|f|<1} by a polygonal path of length strictly below 2. If f is squarefree the two are distinct.

Proof. Multiple roots give a constant path, so assume f squarefree. The Erdős–Herzog–Piranian component lemma [4] gives a component of {|f|<1} containing two roots. Join them by a compact path in that open component, and choose a regular value modulus t<1 larger than max|f| on the path. The component of {|f|<t} containing it has k≥2 roots and hence k−1≥1 critical points, by the component-wise Riemann–Hurwitz count in the proof of [8]. One of these critical points has value of modulus below t<1. This choice of t avoids assuming that the level |f|=1 is regular.

Suppose first that f′ has two distinct zeros. Choose a critical point c minimising |f(c)|, write the other one as c+δ, and put v=f(c), so 0<|v|<1. Monicity gives the exact expansion f(c+d)=d3−32δd2+v. Choose α with α3=v and set b=δ/α; dividing by v gives f(c+αw)/v=Pb(w) with

Pb(w)=w3−32bw2+1.

At the other critical point f(c+δ)=v(1−b3/2), so minimality of |v| is exactly the hypothesis |1−b3/2|≥1.

Under that hypothesis Pb has at least two zeros, with multiplicity, in the closed unit disc. In the strict region a unit-circle zero w would give b=23(w+w−2). Write w3=e2iu; substitution gives

|1−b3/2|2=1+64729cos4⁡u(16cos2⁡u−27)≤1.

Since 16cos2⁡u−27<0, equality requires cos⁡u=0, which gives b=0. Thus the strict region has no unit-circle zero. The radial deformation b↦sb, s≥1, stays in the strict region, since z=b3/2 and |1−z|2>1 give |1−s3z|2−1=s3(s3|z|2−2ℜz)>0. For large s, Rouché’s theorem on |w|=1 compares Psb with −32sbw2, whose modulus 32s|b| exceeds 2≥|w3+1|, so Psb has exactly two zeros in the open unit disc; no zero crosses the circle along the deformation. For the equality case with b≠0, the same radial deformation lies in the strict region for every s>1, and continuity of the root multiset allows s↓1. If b=0, then Pb(w)=w3+1 and all three roots lie on the unit circle.

If Pb(w)=0 and 0≤t≤1, then Pb(tw)=1−t2−t2(1−t)w3, so |w|≤1 gives |Pb(tw)|≤(1−t2)+t2(1−t)|w|3≤1−t3≤1. The whole segment from 0 to w therefore lies in the closed unit sublevel set. Selecting two normalized roots w1,w2 with |wi|≤1, the two segments from c to c+αwi lie in {|f|≤|v|}⊂{|f|<1} and have combined length at most 2|α|=2|v|1/3<2.

If instead f′ has a double zero c, then f(c+d)=d3+v. With α3=−v and ω=e2πi/3, its roots are c+α, c+αω, c+αω2. Averaging their squared moduli gives |c|2+|α|2<1, so |α|<1. Any two segments from c to the roots have total length 2|α|<2, and along either segment the value has modulus |v|(1−t3)<1 away from the root endpoint. ◻

The unit level need not be regular, even when all roots lie in the open unit disc. For example, Q(z)=(z−1)(z+1)(z+9/10) has Q(1/3)=−148/135<−1. Its minimum v on [−9/10,1] occurs at an interior critical point and satisfies v<−1. Set r=|v|−1/3<1. The monic cubic r3Q(z/r) has the three distinct roots −r,−9r/10,r in the open unit disc and a critical value equal to −1. Its unit level is therefore singular, although the cubic path theorem applies.

Sources and scope.

Pendyala [11] proves the separate quartic case; no historical priority for the cubic theorem is asserted here.

About this paper

Authorship and AI use. Will Cook built and directed the research infrastructure and maintains the public release. He reviewed claims when he could. AI agents did most of the research and drafting. Cook did not independently verify every claim.

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