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Reciprocal Sums and the Sylvester Recurrence: Further Results and Proofs

Summary. Integer finite differences exclude nonintegral regular rates and reduce the cubic rate to a polynomial. A square condition in the cubic field and congruences modulo seven then prove irrationality. For rational reciprocal sums with an+1/an2 tending to one, the record derives sufficient Sylvester-recurrence criteria from persistent divisors, bounded numerator increases and weighted crossings of new maxima. The arithmetic estimates needed to apply these criteria to every rational reciprocal sum remain open.

This paper covers cubic and nonintegral regular-rate irrationality, integer-tail arithmetic and sufficient Sylvester-recurrence criteria, with their separate hypotheses and remaining estimates.

It does not establish the validity of claims tagged Lean, which belongs to the cited kernel-checked source, or a solution to Erdős #243, which remains open.

In this paper

Integer numerators, denominators and errors

We retain an unreduced fraction Cn/Dn for each rational tail. This keeps the denominator update multiplicative: removing 1/an from the tail gives

(19)Dn+1=anDn,Cn+1=anCn−Dn.

We measure the difference from the Sylvester recurrence by En=Dn−(an−1)Cn. These are Koizumi’s recurrences [12]; their formal definitions are the denominator update, the numerator update, and the error.

We also consider integer solutions of (19) without initially assuming that Cn/Dn is a reciprocal tail. Here and in the following recurrence sections the indices may start at 0, and En always denotes the error just defined. We state positivity and growth assumptions as they are needed. The terms an are the multipliers, while Cn,Dn are the numerator and denominator. The pseudo-greedy rounding rule is an additional condition giving −Cn/2≤En<Cn/2, whereas the absorption argument below needs only |En|<Cn. At a negative error we write en=−En>0. For an isolated step we use a,D,C∈Z without subscripts.

Proposition 4.1 (update law). For all a,D,C∈Z,

aC−D=C−(D−(a−1)C).

Consequently, every solution of (19) satisfies Cn+1=Cn−En.

Proof. C−(D−(a−1)C)=aC−D. ◻

Cn decreases when En>0, increases when En<0, and stays unchanged when En=0. This is why bounds on the negative error become bounds on upward increments.

Example 4.2 (the Sylvester sequence). Take an=2,3,7,43,1807,… with an+1=an2−an+1, and start the state at D0=C0=1. The two updates give

n an Dn Cn En
0 2 1 1 0
1 3 2 1 0
2 7 6 1 0
3 43 42 1 0
4 1807 1806 1 0

and Dn=an−1 with Cn=1 at every index: if Dn=an−1 and Cn=1 then Cn+1=an−(an−1)=1 and Dn+1=an(an−1)=an+1−1. Hence En=Dn−(an−1)Cn=0 throughout and the numerator never moves, which is Proposition 4.1 in the stationary case.

Construction from the reciprocal sum.

Let Tn=∑k≥n1/ak and suppose T0∈Q. Put D0 equal to a common denominator and Dn=D0a0⋯an−1, and set Cn=DnTn. Then Cn∈Z for every n, and from Tn=1/an+Tn+1 one gets Cn+1=anCn−Dn, which is the tail update. On Sylvester’s sequence Tn=1/(an−1) exactly, so Dn=(an−1)Cn and En=0: the error measures deviation from the telescoping tail identity, and it vanishes identically on the Sylvester orbit.

In Lean, the elementary identities are stated for an abstract integer system, and their application to a rational reciprocal sum has separate statements, including the product condition for a rational reciprocal sum. This passage uses the tail realisation, the denominator realisation and the signed update.

Conversely, the recurrences identify a reciprocal sum when the ratio Cn/Dn tends to zero. Regard that ratio as a real number, the tail ratio. Assume an>0, Dn>0, Cn+1+Dn=anCn and Dn+1=anDn. Dividing the numerator update by anDn gives Cn/Dn=1/an+Cn+1/Dn+1, the one-step reciprocal identity. Iterating gives

C0D0=∑n<N1an+CNDN,

as in the finite telescoping identity. If CN/DN→0, taking the limit identifies ∑n1/an=C0/D0, the series realisation. No growth, error bound or separate rationality hypothesis is used in these three identities. Positivity and the stated limit of Cn/Dn are still required. They prove the direction from recurrences to a series; the construction from a rational reciprocal sum was given above and is also formalised in separate declarations.

Under the relative-error hypothesis used below, the required limit is automatic. Suppose an>1, Cn>0, Dn≥0 and En/Cn→0 on an exact integer orbit. If D0=0, then Dn=0 and En/Cn=1−an≤−1 at every index, a contradiction. Thus D0≥1 and Dn≥D02n. For each ε>0, the update gives Cn+1≤(1+ε)Cn eventually. Taking 0<ε<1 shows that Cn/Dn→0, so the telescoping identity realises the reciprocal sum as C0/D0.

The same assumptions also imply the quadratic growth limit. Put θn=En/Cn. Then an=Dn/Cn+1−θn→∞, and the exact recurrences give

an+1an2=11−θn−1an+1−θn+1an2⟶1.

In particular, the multipliers are strictly increasing eventually. Thus a global orbit with these positivity and relative-error assumptions already gives a sequence of the type in Problem 1.1 after deletion of a finite prefix. No separate tail-limit estimate is needed for such an orbit; without the relative-error assumption, that estimate remains a condition of the general telescoping argument.

Proposition 4.3 (scaling the numerator and denominator). For every s,a,D,C∈Z,

a(sD)=s(aD),a(sC)−sD=s(aC−D),
sD−(a−1)sC=s[D−(a−1)C].

Multiplying the numerator and denominator by the same factor therefore preserves the recurrence and scales the error by that factor. When the factor divides all entries, we can divide it out instead. This is used in the finite calculation of Appendix B and in the induction in Theorem 10.1.

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