Weighted row–column compatibility bound

As $d\to\infty$,
\[
 \|q_d^{*(1600d)}-U_n\|_{\mathrm{TV}}\longrightarrow0.
\]
For every integer $t\ge0$,
\[
 \|q_d^{*t}-U_n\|_{\mathrm{TV}}
 \ge 1-\frac{2^{tn/2}}{n!}.
\]
Consequently the mixing time at distance $1/4$ satisfies
\[
 t_{\mathrm{mix}}(d)\ge
 \left\lceil\frac2n\log_2\frac{3n!}{4}\right\rceil
 =2d-O(1),
 \qquad t_{\mathrm{mix}}(d)=\Theta(d).
\]

Partition $X$ into $b$ nonempty sets $M_1,\ldots,M_b$. Put $H_i=H_{M_i}$. Suppose $f$ is a nonnegative measure on $G$ of mass at most one and, for every $g\in G$ and $i$,
\begin{equation}
 f(gH_i)\le \frac{B}{[G:H_i]}.
\end{equation}
For every $u>0$ and every irreducible $\rho$ of degree $D$,
\begin{equation}
 \|\widehat f(\rho)\|_{\HS}^2
 \le bBC_uD^{-1+(u+2)/b}.
\end{equation}
There is also an independent orbit-span proof of the bound
\begin{equation}
 \|\widehat f(\rho)\|_{\op}^2
 \le bBC_uD^{-1+(u+2)/b}.
\end{equation}
No restriction is imposed on block sizes or on the multiplicities in $\rho|_{H_1\times\cdots\times H_b}$.

Let $n=2^d$, and start the shuffle from any deterministic deck.
After $J(s_0+1)$ sweeps, where $s_0=400$ and $J=40000$, the conditional free-slot law defined above satisfies
\[
 \sup_{\text{initial layouts}}\E_{\mathcal E}
       \|\nu_{\mathcal E}-U_{n/2}\|_{\TV}\longrightarrow0
       \qquad(d\longrightarrow\infty).
\]
Consequently the full-deck law approaches uniform, uniformly in the starting deck, after $16\,040\,400d$ physical shuffles. For every integer $t\ge0$, after $t$ physical shuffles the full-deck distance from uniform is at least
$1-2^{tn/2}/n!$. Thus the full-deck mixing time is of order $d$.

There are absolute constants $\eta,c,C>0$ such that, with $a=1/1000$,
\[
 \log\E_{y\sim u_{N,k}}R_x(y)^{1+a}
 \le Ck(k/N)^\eta
 \qquad(1\le k\le N),
\]
uniformly over every starting injection $x$. For every sufficiently
large dyadic $N$ and every nontrivial irreducible representation,
\[
 T_N(\lambda)=0\quad\hbox{or}\quad
 \|T_N(\lambda)\|_{\op}\le D_\lambda^{-c}.
\]
Consequently an absolute number of forward sweeps has worst-start
total-variation distance from uniform tending to zero as $d\to\infty$.

There are positive weights $W_\lambda$, an absolute finite $p_*$, and real
exponents $2\le p_d\le p_*$ such that, for every $d\ge1$ and every
$\lambda\vdash2^d$,
\begin{equation}
 D_\lambda^{3/4}\le W_\lambda\le D_\lambda,
 \qquad W_\lambda\|K_d(\lambda)\|_{p_d}^{p_d}\le1.
\end{equation}
Consequently $\|K_d(\lambda)\|_{\rm op}\le D_\lambda^{-3/(4p_*)}$.

There is an absolute constant $C$ such that, for every $d\ge1$,
\[
 \left\lceil\frac2N\log_2\frac{3N!}{4}\right\rceil
 \le t_{\rm mix}(d)\le Cd,
 \qquad N=2^d.
\]
In particular $t_{\rm mix}(d)=\Theta(d)$, and its lower bound is
$2d-O(1)$.

There is an absolute $P\ge2$ such that for every dyadic $n\ge2$,
\begin{equation}
 \operatorname{Tr}_{\rm reg}|Q_n|^P\le1+n^{-10}.
\end{equation}
If $v$ is an integer with $2v\ge P$, then $v$ independent sweeps have total-variation distance at most $\frac12n^{-5}$ from uniform, from every deterministic initial deck. Here $\|\mu-\nu\|_{\rm TV}=\tfrac12\sum_g|\mu(g)-\nu(g)|$.

There are absolute constants $L,C_0>0$ such that the following holds. Put $m=\sqrt n$, assume $m/2\le A,D\le2m$, and take $m$ sufficiently large that $\theta=1-L/\log m>0$. For all nonnegative functions $w_i:S_D\to[0,\infty)$ and $v_k:S_A\to[0,\infty)$,
\begin{equation}
 \frac{n!}{|R||C|}\,
 \mathbb E_U\!\left[\mathbf1_{\mathcal I}
       \prod_{i=1}^A w_i(r_i)\prod_{k=1}^D v_k(c_k)\right]
 \le e^{C_0n^{.54}}
       \prod_{i=1}^A(\mathbb E w_i^{1/\theta})^\theta
       \prod_{k=1}^D(\mathbb E v_k^{1/\theta})^\theta .
\end{equation}
The expectations on the right are uniform on the indicated symmetric groups, and logarithms are natural.

There is an absolute finite $p_*>0$ such that, for every dyadic $n$,
\begin{equation}
 Z_n(p_*)\le1+\frac1{16}.
\end{equation}
For every integer $M\ge p_*$, $M$ independent forward sweeps have worst-start total-variation distance at most $1/8$ from uniform.

For every nontrivial $\lambda\vdash n$ and $1\le r\le D_\lambda$,
\[
 s_r(T_{n,\lambda})\le(16D_\lambda r)^{-1/(2p_*)}.
\]
If $s_j(T_n)$ denotes the full regular singular list, including all multiplicities and zeros, then
\[
 s_j(T_n)\le j^{-1/(2p_*)}\qquad(1\le j\le n!).
\]
The constant singular value is the first value. The physical Thorp chain has worst-start $1/4$ mixing time $\Theta(d)$; more precisely its lower bound is $2d-O(1)$. For every fixed integer $M>p_*$, the worst-start total-variation distance after $Md$ physical shuffles tends to zero as $d\to\infty$.

For each sufficiently small fixed $\bar\eta>0$, choose a sufficiently
small $\bar\kappa>0$ with $\bar\kappa<\bar\eta/256$. There is an
integer $r\ge1$, depending only on these fixed constants, such that for
every $d\ge1$, every $\lambda\vdash n=2^d$, and every
occurrence~\eqref{ten:spin:eq:1},
\begin{equation}
 \log\!\left(D_\lambda\operatorname{Tr}_{V_\lambda}(B_n^*B_n)^r\right)
 \le\eta_d F(\alpha,\beta)+g_n(l),
\end{equation}
where
\[
 \eta_d=\bar\eta\left(1-\frac1{2\sqrt d}\right),\qquad
 \kappa_d=\bar\kappa\left(1-\frac1{2\sqrt d}\right),\qquad
 g_n(l)=\max\{0,\kappa_d l\log n-l\log(n/l)\}.
\]
Set $g_n(0)=0$ and interpret the logarithm of a zero trace as $-\infty$.

There is an absolute positive integer $L$ such that
\[
 \mathbb E_{U_{S_n}}|f_{d,L}-1|^2\longrightarrow0
 \qquad(d\longrightarrow\infty).
\]
The convergence is uniform over starting orders. Moreover
$t_{\mathrm{mix}}(d)=\Theta(d)$.

There are absolute constants \(g>0\) and \(d_0\) such that, for \(d\ge d_0\)
and every \(\lambda\vdash 2^d\),
\[
 \|K_\lambda\|_{\op}\le D_\lambda^{-g}.
\]
The sign representation is annihilated. There is an absolute positive integer \(w\)
such that the law after \(w\) independent sweeps converges to uniform in
total variation as \(d\to\infty\), uniformly over deterministic initial
decks.

For every integer \(t\ge0\),
\[
 \|q_d^{*t}-U_N\|_{\TV}\ge1-\frac{2^{tN/2}}{N!}.
\]
Consequently,
\[
 t_{\rm mix}(d)\ge
 \left\lceil\frac2N\log_2\!\left(\frac{3N!}{4}\right)\right\rceil
 =2d-O(1).
\]

There are absolute constants $p_0\in(4/3,2)$ and $\varepsilon>0$ with the following property. Let $\nu$ be a probability measure on $S_4$ such that
\[
 \|\nu-u\|_{\TV}<\varepsilon,
 \qquad
 \nu\{\pi:\pi(i)=j\}=\frac14\quad(1\le i,j\le4).
\]
Then every four nonnegative functions on $\{1,2,3,4\}$ satisfy
\begin{equation}
 \E_\nu\prod_{i=1}^4f_i(\pi(i))\le\prod_{i=1}^4\|f_i\|_{p_0}.
\end{equation}

There exist an even integer $r\ge2$ and $\eta>0$, independent of $N$, such that for every dyadic $N$ and every $\lambda\vdash N$,
\begin{equation}
 D_\lambda\Tr B_N(\lambda)^r\le D_\lambda^{1-\eta}.
\end{equation}
Consequently there is an absolute integer $q$ for which the total-variation distance of $q$ independent forward sweeps from uniform tends to zero as $N\to\infty$, uniformly over the starting deck.