Lean is a language for mathematical statements and proofs that a computer can verify. This page shows one statement file from OpenAI’s release, possible paper matches and independent reports. The code-like names below identify the definitions or theorems selected by the proof-verification settings.
Theorem selected for verification:OAI.PeriodicTilingThree.periodic_tiling_counterexample_and_minimality
The lines of the Lean statement that state the theorem, then the definitions in the file that it uses.
theoremperiodic_tiling_counterexample_and_minimality : (∃ T : Finset (Lattice 3), T.Nonempty ∧ (∃ A : Set (Lattice 3), Tiles T A) ∧ (∀ A : Set (Lattice 3), Tiles T A → ¬ FullyPeriodic A) ∧ (∃ A : Set (Space 3), AETiles (Thickening T) A) ∧ (∀ A : Set (Space 3), AETiles (Thickening T) A → ¬ EuclideanFullyPeriodic A)) ∧ IsLeast {d : ℕ | HasTileWithoutPeriodicComplement d} 3 := bysorry
A Lean statement states the theorem and leaves its proof as sorry on purpose. OpenAI’s proof is in a separate solution module, and a program called Comparator checks that proof against this statement.
Definitions needed to read it
Local definitions the statement names, followed through the definitions they name in turn. The match is by name in the source text, so a name reached only through notation can be missed; the full file is below.
defHasTileWithoutPeriodicComplement (d : ℕ) : Prop := ∃ T : Finset (Lattice d), T.Nonempty ∧ (∃ A : Set (Lattice d), Tiles T A) ∧ ∀ A : Set (Lattice d), Tiles T A → ¬ FullyPeriodic A
Possible paper match, with no recorded review
No paper statement clearly matched the Lean wording. Statement Map, the program that collects Atlas’s source records, selected this possible match using words in OpenAI’s catalogue and Lean note. No review of whether the statements mean the same thing is recorded.
Shared with the catalogue’s wording or OpenAI’s note, none of them matched in the Lean text: finite, index, invariant, lattice, subgroup, tiles, tiling and translation.
Theorem 1.1 of A translational tile with no fully periodic tiling in dimension three
Theorem
There is a finite nonempty set T\subset\Z^3 such that:
(i)
T tiles \Z^3 by translations, but no translation set A with A\oplus T=\Z^3 is invariant under a subgroup of finite index in \Z^3;
(ii)
the set \Omega=T+[0,1]^3 tiles \R^3 by translations up to null sets, but no such tiling has a translation set invariant under a lattice of full rank in \R^3.
There is a finite nonempty set $T\subset\Z^3$ such that:
\begin{enumerate}[label=\textup{(\roman*)}]
\item $T$ tiles $\Z^3$ by translations, but no translation set $A$ with $A\oplus T=\Z^3$ is invariant under a subgroup of finite index in $\Z^3$;
\item the set $\Omega=T+[0,1]^3$ tiles $\R^3$ by translations up to null sets, but no such tiling has a translation set invariant under a lattice of full rank in $\R^3$.
\end{enumerate}
Other possible paper matches, closest wording first
Proposition 7.5 of A translational tile with no fully periodic tiling in dimension three. Words of the Lean statement, its names split into words, that also appear in the theorem: euclidean, lattice, tile and tiling. Shared only with the release’s name for the Lean statement or OpenAI’s note on it: almost, everywhere, translational, translation and invariant.
Corollary 6.3 of A translational tile with no fully periodic tiling in dimension three. Words of the Lean statement, its names split into words, that also appear in the theorem: integer, fully, periodic, tile, nonempty, finite and one more. Shared only with the release’s name for the Lean statement or OpenAI’s note on it: admits.
Proposition 6.2 of A translational tile with no fully periodic tiling in dimension three. Words of the Lean statement, its names split into words, that also appear in the theorem: fully, periodic, nonempty, finite and tiles.
Proposition 2.4 of A translational tile with no fully periodic tiling in dimension three. Words of the Lean statement, its names split into words, that also appear in the theorem: period.
Theorem 5.2 of A translational tile with no fully periodic tiling in dimension three. Words of the Lean statement, its names split into words, that also appear in the theorem: subgroup, index, nonempty, finite and tiling. Shared only with the release’s name for the Lean statement or OpenAI’s note on it: invariant.
Proposition 7.2 of A translational tile with no fully periodic tiling in dimension three. Words of the Lean statement, its names split into words, that also appear in the theorem: tile and tiles.
How Atlas selects possible matches: it compares words in the Lean statement with every statement in the family. It also splits Lean names into words. The release’s label and note receive less weight; a main theorem wins a close match. If the Lean wording yields no clear match, Atlas uses the catalogue description. This selects passages to compare; it does not establish that they mean the same thing.
Reported Comparator runs
two independent groups report that Comparator accepted runs for this Lean statement file: Carlos Toledo’s cert-machine; MathVet. Each group reports its own Comparator run for this statement file. Atlas has not repeated the runs.
For a configured theorem, Comparator tests whether OpenAI’s proof proves the exact Lean statement. Some files instead configure definitions for comparison by name and type. Acceptance does not establish that the statement means the same thing as the paper’s theorem.
Every Comparator challenge re-run on Linux with nanoda switched on, decided by a preregistered rule; every family’s challenge statements read against OpenAI’s headline, clause by clause. Decider: Comparator (leanprover/comparator d03acab1 = tag v4.34.0, built with the release’s toolchain v4.34.1), lean4export 076e8e57, landrun 811cfff5, nanoda_lib 3a240721 — on GitHub’s Linux runners (.github/workflows/openai-math-kernel.yml), one j…
AcceptedTheir term: “CERTIFIED”.
Re-run through Comparator with the independent nanoda kernel switched on: Lean’s kernel and nanoda both accept OpenAI’s solution.
An independent, model-assisted, pre-referee reading of each family’s challenge statements against its headline claim under a published rubric (PROTOCOL.md), with its own Comparator runs per challenge. Its protocol describes a planned error-rate study; this import does not establish that the study has been completed.
AcceptedTheir term: “comparator-sandboxed-pass”.
Re-run through Comparator in a sandboxed virtual machine: accepted.
If Comparator is run under this configuration and accepts, the solution proves the configured theorem using only the allowed axioms, and the Lean kernel accepts every step.
This configuration lists no definition holes, so every definition the statement uses is compared as it is written in this file.
Acceptance leaves open whether the Lean statement means the same thing as the paper’s theorem, whether the paper’s other claims are correct, and whether the result is new. Those questions require comparing the definitions and statements, reviewing the paper’s arguments, and reading the earlier literature.
Do family 155’s Lean statements express the advertised result?
These assessments compare all the family’s Lean statements with the whole result OpenAI describes in its catalogue. They do not assess this statement alone. Each group uses its own published rules.
MathVet and cert-machine agree on how much of the advertised result the Lean statements express.
Finds the whole advertised result stated or impliedTheir term: “full”.
The challenge statements imply the headline claim after unpacking definitions or one routine step. Their record
Their note: One conjunction states all three parts: a nonempty finite T ⊆ ℤ³ with Tiles T A for some A but no FullyPeriodic (finite-index-subgroup invariant) tiling complement; the unit-cube thickening T + [0,1]³ a.e.-tiles ℝ³ by some arbitrary real translation set A but by none invariant under a full-rank lattice; and IsLeast {d | HasTileWithoutPeriodicComplement d} 3 (minimality, which absorbs the d = 1, 2 periodicity theorems). Tiles is exact (bijective F × A → G) and the ℝ³ version uses closed cubes with AETiles (unique representation a.e.), matching the summary and docs.
Definitions the group asks readers to compare with the paper: abbrev Lattice (d : ℕ) := Fin d → ℤ shadows Mathlib's Lattice class name inside the namespace (harmless; means ℤ^d)
OpenAI’s own note on what this Lean statement covers
“The formalized counterexample is a finite tile in $\mathbb Z^3$ that tiles but has no complement invariant under a finite-index subgroup. Its unit-cube thickening also tiles $\mathbb R^3$ almost everywhere but admits no fully periodic tiling, even with arbitrary real translation vectors. The result also establishes that dimension three is the least lattice dimension where this failure occurs.”
An AI agent drafted an interpretation of that note, classifying this statement as “states a paper’s theorem as the paper does”. No human review of the draft is recorded.
Supporting material
The complete Lean statement file
66 lines, copied from release version fd4aeeb. A name defined in this file links to its line; pointing at the name shows its definition.
Declared in this fileOpenAI’s library at fd4aeebOther linked names open the current documentation for Mathlib, Lean’s mathematical library.
Links in the file: 36 to its own declarations, 32 to Mathlib’s documentation. 13 declared names also link to the same declaration in OpenAI’s library. OpenAI uses Mathlib version d13f23b. The linked documentation describes the current version, so names that have since changed may be missing there.
There is a finite nonempty set T\subset\Z^3 such that:
(i)
T tiles \Z^3 by translations, but no translation set A with A\oplus T=\Z^3 is invariant under a subgroup of finite index in \Z^3;
(ii)
the set \Omega=T+[0,1]^3 tiles \R^3 by translations up to null sets, but no such tiling has a translation set invariant under a lattice of full rank in \R^3.
There is a finite nonempty set $T\subset\Z^3$ such that:
\begin{enumerate}[label=\textup{(\roman*)}]
\item $T$ tiles $\Z^3$ by translations, but no translation set $A$ with $A\oplus T=\Z^3$ is invariant under a subgroup of finite index in $\Z^3$;
\item the set $\Omega=T+[0,1]^3$ tiles $\R^3$ by translations up to null sets, but no such tiling has a translation set invariant under a lattice of full rank in $\R^3$.
\end{enumerate}
propext, Quot.sound, Classical.choiceThe axioms this configuration allows a proof to use. A replay shows which of them a proof uses.
Imports
Mathlib
Imports from outside Mathlib
None
Local vocabulary
12 local vocabulary declarations
Lines of Lean, without comments or blank lines
34
Second proof-verification program (nanoda)
Off in OpenAI's configuration.
Statement comparison
A shareable summary of this page: the proposed paper match, what the Lean statement expresses, and which reviews are recorded.
Plectis Atlas
Aperiodic translational tile in dimension three
Family 155: A counterexample to periodic tiling in dimension three
Candidate pairing
Theorem
There is a finite nonempty set T\subset\Z^3 such that:
(i)
T tiles \Z^3 by translations, but no translation set A with A\oplus T=\Z^3 is invariant under a subgroup of finite index in \Z^3;
(ii)
the set \Omega=T+[0,1]^3 tiles \R^3 by translations up to null sets, but no such tiling has a translation set invariant under a lattice of full rank in \R^3.
A translational tile with no fully periodic tiling in dimension three
TeX label thm:main, build/paper.tex, line 79
The Lean statement says
theoremperiodic_tiling_counterexample_and_minimality : (∃ T : Finset (Lattice 3), T.Nonempty ∧ (∃ A : Set (Lattice 3), Tiles T A) ∧ (∀ A : Set (Lattice 3), Tiles T A → ¬ FullyPeriodic A) ∧ (∃ A : Set (Space 3), AETiles (Thickening T) A) ∧ (∀ A : Set (Space 3), AETiles (Thickening T) A → ¬ EuclideanFullyPeriodic A)) ∧ IsLeast {d : ℕ | HasTileWithoutPeriodicComplement d} 3 := bysorry
A Lean statement states the theorem and leaves its proof as sorry on purpose. OpenAI’s proof is in a separate solution module, and a program called Comparator checks that proof against this statement.
Recorded comparisons with the paper
Atlas records no contributed comparison of this statement with the paper.
Contributed Comparator run reports
Atlas records no contributed report of running Comparator for this statement file.
More about this statement
Commentary An expert notes that the result is weak aperiodicity rather than strong, that the paper does not mention that distinction or the work on connected tiles, and that a connected tile in three dimensions follows without extra dimensions. Joseph Myers, Comments on the translational tile manuscript, 2026-10-08Source
Follow-up result Demaine and Langerman adapt OpenAI's cyclic tiling encoding from its 3D aperiodic-tile paper to show that translational monotiling by one connected polycube in 3D is undecidable. Erik D. Demaine, Stefan Langerman, Tiling 3D by Translates of a Single Polycube is Undecidable, 2026-10-08Source
Commentary A tiling expert quoted by Quanta says the three-dimensional aperiodic tile paper has novel ideas but is hard to read and would not be publishable by traditional standards. Konstantin Kakaes, Quanta: Cracks appear in OpenAI's wall of proofs (and the 6 October piece), 2026-10-09Source