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Irrational cubic fourfolds with Hodge-theoretic and categorical K3 associations

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For every sufficiently large admissible Hassett discriminant, a very general smooth complex cubic fourfold is irrational despite having both an untwisted geometric K3 category and an integral Hodge-theoretic K3 association. This disproves Kuznetsov’s rationality conjecture and the sufficiency of the associated-K3 criterion for rationality; the discriminant threshold is ineffective.

The release has no Lean statement for this family, so there is no formal statement to compare with the result described above.

What the papers state

Theorem 1.1 (Irrationality on large admissible Hassett divisors)

In Irrational cubic fourfolds with geometric K3 categories, 24 September 2026

The paper’s main theorem is shown as a possible match to OpenAI’s description. No review confirming the selection is recorded.

There is an integer d_0 such that, for every admissible d>d_0, a very general cubic fourfold X in \mathcal C_d is irrational and admits an exact \C-linear equivalence

\Ku(X)\simeq D^b(\operatorname{Coh}S)

for a smooth projective K3 surface S.

Corollary 1.2 (Failure of associated-K3 sufficiency)

In Irrational cubic fourfolds with geometric K3 categories, 24 September 2026

Possible match to OpenAI’s description, selected because it shares the most wording. No review confirming the selection is recorded.

Let d_0 be the threshold in Theorem 1.1. For every admissible d>d_0, a very general X\in\mathcal C_d is irrational and admits a labelling K of discriminant d and a primitively polarized smooth projective K3 surface (S_{\mathrm{Hdg}},L), with L^2=d, for which there is an integral Hodge isometry

K^\perp \simeq L^\perp(-1).

Here L^\perp\subset H^2(S_{\mathrm{Hdg}},\Z), and the surface cup pairing is reversed. Thus an associated untwisted polarized K3 surface in this Hodge-theoretic sense is not sufficient for rationality.

The release does not say which paper theorem its catalogue describes. Both statements above are shown whole: the paper’s main theorem first, then the statement that shares the most wording with the description. The atlas has not reviewed either choice.

Two more possible matches

  • Corollary 1.4 (Integral Chow decompositions for the irrational cubics) in Irrational cubic fourfolds with geometric K3 categories, 24 September 2026.
  • Corollary 1.3 (Failure of Hilbert-square sufficiency) in Irrational cubic fourfolds with geometric K3 categories, 24 September 2026.
Reported proof verification
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Papers

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Irrational cubic fourfolds with geometric K3 categories

24 September 2026, current edition.

Read it herePDF

For every sufficiently large admissible Hassett discriminant, we prove that a very general cubic fourfold of that discriminant is irrational, although its Kuznetsov component is equivalent to the ordinary derived category of a projective K3 surface. The discriminant threshold is ineffective. This disproves Kuznetsov’s rationality conjecture. The same cubics have associated untwisted polarized K3 surfaces in the Hodge-theoretic sense, so they also disprove the sufficiency direction of the associated-K3 rationality prediction.

Lean statements

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Independent comparisons and proof-verification reports

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What these papers cite in the release, and what cites them

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Papers elsewhere in the release that this family’s papers cite

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Papers elsewhere in the release that cite this family’s papers

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References outside the release

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What people have said

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  • An unsigned public tier list, the OpenAI Math Tier List, classes it as a counterexample and rates its significance, if it holds up, as “Career-defining publication”. The page says that nothing on it is verified.

    Author not stated. Source

Questions awaiting review

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Identify the theorem the catalogue describes

  • Family 054 The theorem shown was selected from shared wording with OpenAI’s description. Atlas records no review confirming that it is the theorem the description means. Open the form

State the result in Lean

  • Family 054 The release has no Lean statement for this family. Open the form